0

我有一个很好的下拉列表，它是从表团队（FK）中填充的。唯一不起作用的是将数据添加到匹配项中。我不断收到以下错误：

- team_home not set 
- team_away not set 

- Notice: Undefined index: team_home in vvo/insertmatch.php on line 28

- Notice: Undefined index: team_away in vvo/insertmatch.php on line 28

- Error: You have an error in your SQL syntax; check the manual that corresponds to your    MySQL server version for the right syntax to use near 'matches (team_home, team_away) VALUES ('','')' at line 1

谁能告诉我是什么导致了这些错误？

请参阅下面的代码，我知道它很容易受到 sql 注入的影响，但我只想让它工作。

**addmatch.php**

<?php
$con = mysql_connect("db.xx.nl","md190851db210288","xxx");
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }

mysql_select_db("md190851db210288", $con);

?>
<form action="insertmatch.php" method="GET">
<select name="team_home">
<?php
$sql = "SELECT team_id, team_name FROM teams ".
"ORDER BY team_name";

$rs = mysql_query($sql);

while($row = mysql_fetch_array($rs))
{
  echo "<option value=\"".$row['team_id']."\">".$row['team_name']."</option>\n  ";
}
?>
</select>
<select name="team_away">
<?php
$sql = "SELECT team_id, team_name FROM teams ".
"ORDER BY team_name";

$rs = mysql_query($sql);

while($row = mysql_fetch_array($rs))
{
  echo "<option value=\"".$row['team_id']."\">".$row['team_name']."</option>\n  ";
}
?>
</select>
<input type="submit" />


**insertmatch.php**

<?php
  error_reporting(E_ALL);
  ini_set("display_errors", 1);

$con = mysql_connect("db.xx.nl","md190851db210288","xxx");
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }

if (isset($_POST['team_home'])) { 
    echo $_POST['team_home']; 
} else { 
    echo 'team_home not set <br>'; 
}
if (isset($_POST['team_away'])) { 
    echo $_POST['team_away']; 
} else { 
    echo 'team_away not set <br>'; 
}  

mysql_select_db("md190851db210288", $con);

$sql="INSERT INTO matches (team_home, team_away)
VALUES
('$_POST[team_home]','$_POST[team_away]')";

if (!mysql_query($sql,$con))
  {
  die('Error: ' . mysql_error());
  }
echo "1 record added";

echo $team_home;
?>
4

3 回答 3

2

试试这个

$sql=sprintf("INSERT INTO matches (team_home, team_away)VALUES('%s','%s')",mysql_real_escape_string($_POST['team_home']),mysql_real_escape_string($_POST['team_away']));
于 2012-04-11T19:32:16.643 回答
1

您的 PHP 无效：

$_POST[team_home]

双引号里面是错误的。

在它周围加上 {}，在 team_home 周围加上单引号

{$_POST['team_home']}

and similarly for other fields. And as suggestion be aware from SQL injection, and sanitize data from $_POST before usino it in queries

于 2012-04-11T19:33:29.243 回答
0

只是想指出你在这里做什么

$sql="INSERT INTO matches (team_home, team_away)
VALUES
('$_POST[team_home]','$_POST[team_away]')";

非常危险。您不应该直接使用任何全局变量。您需要过滤并验证它们，否则您的应用程序将受到 SQL 注入攻击。

于 2012-04-11T19:33:25.437 回答