codeigniter - Codeigniter Where 子句

Question

不知何故，对我来说构建这样的查询有点困难：给我所有链接名不为空的导航条目

$query = $this->db->get_where('navigation',array('linkname'!==NULL));

给我错误

“where子句”中的未知列“0”

选择linkname,idnavigation从 ( navigation) WHERE 0= 1

有什么提示吗？

score 12 · Accepted Answer

您可以像这样简单地手动编写WHERE子句：

$this->db->get_where('navigation', 'linkname IS NOT NULL');

score 1 · Accepted Answer

1

它的：

$query = $this->db->get_where('navigation',array('linkname !=' => NULL));

于 2012-04-11T15:33:53.273 回答

score 0 · Accepted Answer

0

试试这个...

$this->db->select("*)
->from("table_name")
->where("your_id <>",'');

于 2014-12-15T09:22:10.117 回答

score -2 · Accepted Answer

-2

$this->db->where('linkname !==', NULL);
$query = $this->db->get('navigation');

于 2012-04-11T15:30:01.050 回答

4 回答 4