2

所以这是我的问题,我有一个带有以下键 => 值的字典:

6bc51fb21fd9eefef4ec97a241733cd59b71e8e14ad70e9068d32002:политичка -> 2
6bc51fb21fd9eefef4ec97a241733cd59b71e8e14ad70e9068d32002:државата -> 2
6bc51fb21fd9eefef4ec97a241733cd59b71e8e14ad70e9068d32002:енергично -> 1
1caa60ebf9459d9cd406f1a03e1719b675dcfaad78292edc7e4a56be:полициска -> 1

我有这段代码来显示所需的键:

for key, value in count_db.iteritems():
        print key[:56]

所以现在我有:

6bc51fb21fd9eefef4ec97a241733cd59b71e8e14ad70e9068d32002 -> 2
6bc51fb21fd9eefef4ec97a241733cd59b71e8e14ad70e9068d32002 -> 2
6bc51fb21fd9eefef4ec97a241733cd59b71e8e14ad70e9068d32002 -> 1
1caa60ebf9459d9cd406f1a03e1719b675dcfaad78292edc7e4a56be -> 1

我需要将它们合并到:

6bc51fb21fd9eefef4ec97a241733cd59b71e8e14ad70e9068d32002 -> 5
1caa60ebf9459d9cd406f1a03e1719b675dcfaad78292edc7e4a56be -> 1

我已经做到了,但我没有正确地做到这一点:

length_dic=len(count_db.keys())
for key, value in count_db.iteritems():
    count_element=key[:56]
    #print "%s => %s" % (key[:56], value) #value[:56]

    for i in range(length_dic):
        i+=1
        if count_element == key[:56]:
            itr+=int(value) 
        print i
    length_dic=length_dic-1

有什么提示吗?

4

4 回答 4

4

一个简单的方法是:

result = {}
for key, value in count_db.iteritems():
    result[key[:56]] = result.get(key[:56], 0) + value

reduce如果你想在一行上得到它,你也可以达到同样的效果:

import collections
result = reduce(lambda x,y: x[y[0][:56]] += y[1] , count_db.iteritems(), collections.defaultdict(int))
于 2012-04-11T12:05:55.347 回答
1

鉴于您的字典为

>>> spam={"6bc51fb21fd9eefef4ec97a241733cd59b71e8e14ad70e9068d32002:AAAA": 2,
"6bc51fb21fd9eefef4ec97a241733cd59b71e8e14ad70e9068d32002:BBBB": 2,
"6bc51fb21fd9eefef4ec97a241733cd59b71e8e14ad70e9068d32002:CCCC": 1,
"1caa60ebf9459d9cd406f1a03e1719b675dcfaad78292edc7e4a56be:DDDD": 1
}

你可以像下面这样

>>> bacon=collections.defaultdict(int)
>>> for k,v in [(k[:56],v) for k,v in spam.iteritems()]:
    bacon[k]+=v


>>> bacon
defaultdict(<type 'int'>, {'6bc51fb21fd9eefef4ec97a241733cd59b71e8e14ad70e9068d32002': 5, '1caa60ebf9459d9cd406f1a03e1719b675dcfaad78292edc7e4a56be': 1})
>>> 
于 2012-04-11T12:09:47.227 回答
0

我不明白你为什么在代码中做了所有这些。我认为这可以完成这项工作:

tmp_dict = {}
for key, value in count_db.iteritems():
    count_element=key[:56]

    if count_element in tmp_dict:
        tmp_dict[count_element] += value
    else:
        tmp_dict[count_element] = value
于 2012-04-11T12:11:57.033 回答
0

这正是Counter对象(在 2.7+ 版本中)的用途:

import collections
c = collections.Counter()

for key, value in count_db.iteritems():
    c[key[:56]] += value
于 2012-04-11T17:48:57.617 回答