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我正在使用带有 wampserver 的 php 5.2.4。一切顺利。我在几天内完成了几项工作。没有问题。

但我面临一个特殊的问题。我为该页面编写的脚本正在显示而不是呈现的网页。我的页面在这里给出：

<?php
if(isset($_POST['email'])) {

    // EDIT THE 2 LINES BELOW AS REQUIRED
    $email_to = "abdrhm30@yahoo.com";
    $email_subject = "Your email subject line";


    function died($error) {
        // your error code can go here
        echo "We are very sorry, but there were error(s) found with the form you submitted. ";
        echo "These errors appear below.<br /><br />";
        echo $error."<br /><br />";
        echo "Please go back and fix these errors.<br /><br />";
        die();
    }

    // validation expected data exists
    if(!isset($_POST['first_name']) ||
        !isset($_POST['last_name']) ||
        !isset($_POST['email']) ||
        !isset($_POST['telephone']) ||
        !isset($_POST['comments'])) {
        died('We are sorry, but there appears to be a problem with the form you submitted.');       
    }

    $first_name = $_POST['first_name']; // required
    $last_name = $_POST['last_name']; // required
    $email_from = $_POST['email']; // required
    $telephone = $_POST['telephone']; // not required
    $comments = $_POST['comments']; // required

    $error_message = "";
    $email_exp = '/^[A-Za-z0-9._%-]+@[A-Za-z0-9.-]+\.[A-Za-z]{2,4}$/';
  if(!preg_match($email_exp,$email_from)) {
    $error_message .= 'The Email Address you entered does not appear to be valid.<br />';
  }
    $string_exp = "/^[A-Za-z .'-]+$/";
  if(!preg_match($string_exp,$first_name)) {
    $error_message .= 'The First Name you entered does not appear to be valid.<br />';
  }
  if(!preg_match($string_exp,$last_name)) {
    $error_message .= 'The Last Name you entered does not appear to be valid.<br />';
  }
  if(strlen($comments) < 2) {
    $error_message .= 'The Comments you entered do not appear to be valid.<br />';
  }
  if(strlen($error_message) > 0) {
    died($error_message);
  }
    $email_message = "Form details below.\n\n";

    function clean_string($string) {
      $bad = array("content-type","bcc:","to:","cc:","href");
      return str_replace($bad,"",$string);
    }

    $email_message .= "First Name: ".clean_string($first_name)."\n";
    $email_message .= "Last Name: ".clean_string($last_name)."\n";
    $email_message .= "Email: ".clean_string($email_from)."\n";
    $email_message .= "Telephone: ".clean_string($telephone)."\n";
    $email_message .= "Comments: ".clean_string($comments)."\n";

     echo "<br>";
     echo $email_from + $email_to + $email_message;
      echo "<br>";

// create email headers
$headers = 'From: '.$email_from."\r\n".
'Reply-To: '.$email_from."\r\n".
'X-Mailer: PHP/' . phpversion();
@mail($email_to, $email_subject, $email_message, $headers); 
}
?>

当我从 phpmyadmin 运行它时，它在页面的左上角显示 0。我检查了 short_tag ，重新启动了服务器两次。但没有结果。我能做些什么？

4

3 回答 3

1

创建一个文件 phpinfo.php 并在其中添加以下代码：

phpinfo();

如果您仍然能够看到代码，请重新安装您的 wampserver 并确保 Apache 服务器正在运行。

于 2012-04-11T08:10:55.140 回答
1

您对字符串连接如何与 javascript 一起工作感到困惑。我的意思是这一行：

echo $email_from + $email_to + $email_message;

将其替换为

echo $email_from . $email_to . $email_message;
于 2012-04-11T08:37:01.557 回答
0

检查空格

还 - 从您的 PHP 文件末尾删除 ?>，这也可能导致输出错误

于 2012-04-11T08:37:13.460 回答