2

如何在php中以hrs min sec格式获取start_date和end_date之间的持续时间？

$start_date=2012-03-23 11:58:14  and $end_date=2012-03-24 11:54:29
4

5 回答 5

5

使用DateTime类：

$start_date = new DateTime('2012-03-23 11:58:14');
$end_date = new DateTime('2012-03-24 11:54:29');

$dd = date_diff($end_date, $start_date);

获取小时使用$dd->h，分钟 - $dd->i，秒 - $dd->s。

echo "Hours = $dd->h, Minutes = $dd->i, Seconds = $dd->s";
于 2012-04-11T04:51:13.750 回答
2

我会 

$start_time = strtotime($start_date);
$end_time = strtotime($end_date);
$difference = $end_time - $start_time;
echo date('H:i:s', $difference);

编辑

我在假设时差小于一天时犯了一个错误，所以如果时差大于一天，你只会看到 Hours:minuetes:seconds，这可能不是你想要的（如果它是忽略这个）

所以我现在会 

$seconds = $difference % 60;            //seconds
$difference = floor($difference / 60);
$min = $difference % 60;              // min
$difference = floor($difference / 60);
$hours = $difference;  //hours
echo "$hours : $min : $seconds";

抱歉更正

于 2012-04-11T04:51:54.900 回答
0

这个功能可以帮助你

function datediff($interval, $datefrom, $dateto, $using_timestamps = false) {
 /*
  $interval can be:
  yyyy - Number of full years
  q - Number of full quarters
  m - Number of full months
  y - Difference between day numbers
   (eg 1st Jan 2004 is "1", the first day. 2nd Feb 2003 is "33". The datediff is "-32".)
  d - Number of full days
  w - Number of full weekdays
  ww - Number of full weeks
  h - Number of full hours
  n - Number of full minutes
  s - Number of full seconds (default)
 */

http://php.net/manual/en/function.date-diff.php

于 2012-04-11T04:48:34.580 回答
0
  1. 将这些字符串格式化为日期
  2. 将这些日期转换为毫秒
  3. 做 endate - stardate
  4. 从结果计算 h:mm:ss
于 2012-04-11T04:49:10.163 回答
0

看到它在这里工作：http ://codepad.viper-7.com/FPuOks

$start_date="2012-03-22 11:58:14";
$end_date="2012-03-24 11:54:29";

$start_time = strtotime($start_date);
$end_time = strtotime($end_date);
$difference = $end_time - $start_time;

echo sprintf("%02d%s%02d%s%02d", floor($difference/3600), ':', ($difference/60)%60, ':', $difference%60); // outputs 47:56:15
于 2012-04-11T06:25:05.890 回答