好的,我的 android 游戏运行流畅,但无法升级。我也收到此警告:说明资源路径位置类型类型安全:方法 addElement(Object) 属于原始类型 Vector。对泛型类型 Vector 的引用应该参数化 LevelManager.java/FROZEN BUBBLES/src/org/bigdaddyapp/android/frozenbubbles 第 32 行 Java 问题
import android.os.Bundle;
import java.util.Vector;
public class LevelManager {
private int currentLevel;
private Vector levelList;
public void saveState(Bundle map) {
map.putInt("LevelManager-currentLevel", currentLevel);
}
public void restoreState(Bundle map) {
currentLevel = map.getInt("LevelManager-currentLevel");
}
public LevelManager(byte[] levels, int startingLevel) {
String allLevels = new String(levels);
currentLevel = startingLevel;
levelList = new Vector();
int nextLevel = allLevels.indexOf("\n\n");
if (nextLevel == -1 && allLevels.trim().length() != 0) {
nextLevel = allLevels.length();
}
while (nextLevel != -1) {
String currentLevel = allLevels.substring(0, nextLevel).trim();
levelList.addElement(getLevel(currentLevel));
allLevels = allLevels.substring(nextLevel).trim();
if (allLevels.length() == 0) {
nextLevel = -1;
} else {
nextLevel = allLevels.indexOf("\n\n");
if (nextLevel == -1) {
nextLevel = allLevels.length();
}
}
}
if (currentLevel >= levelList.size()) {
currentLevel = 0;
}
}
private byte[][] getLevel(String data) {
byte[][] temp = new byte[8][12];
for (int j = 0; j < 12; j++) {
for (int i = 0; i < 8; i++) {
temp[i][j] = -1;
}
}
int tempX = 0;
int tempY = 0;
for (int i = 0; i < data.length(); i++) {
if (data.charAt(i) >= 48 && data.charAt(i) <= 55) {
temp[tempX][tempY] = (byte) (data.charAt(i) - 48);
tempX++;
} else if (data.charAt(i) == 45) {
temp[tempX][tempY] = -1;
tempX++;
}
if (tempX == 8) {
tempY++;
if (tempY == 12) {
return temp;
}
tempX = tempY % 2;
}
}
return temp;
}
public byte[][] getCurrentLevel() {
if (currentLevel < levelList.size()) {
return (byte[][]) levelList.elementAt(currentLevel);
}
return null;
}
public void goToNextLevel() {
currentLevel++;
if (currentLevel >= levelList.size()) {
currentLevel = 0;
}
}
public void goToFirstLevel() {
currentLevel = 0;
}
public int getLevelIndex() {
return currentLevel;
}
}