首先，提前感谢您的帮助。这个问题快把我逼疯了。
我有一个接受 c 字符串的程序，然后可以计算元音和辅音的数量。这没有问题。但是，我还需要包含一个允许用户创建新字符串的函数。但是，问题是，当用户从菜单中选择“新字符串”时，它只是循环执行该newString()方法，而无需等待用户输入。然后它会创建一个新的空白屏幕。
这是整个程序。newString()方法在最后。
#include <iostream>
using namespace std;
// function prototype
void printmenu(void);
int vowelCount(char *);
int consCount(char *);
int cons_and_vowelCount(char *);
void newString(char *, const int);
int main() {
const int LENGTH = 101;
char input_string[LENGTH]; //user defined string
char choice; //user menu choice
bool not_done = true; //loop control flag
// create the input_string object
cout << "Enter a string of no more than " << LENGTH-1 << " characters:\n";
cin.getline(input_string, LENGTH);
do {
printmenu();
cin >> choice;
switch(choice)
{
case 'a':
case 'A':
vowelCount(input_string);
break;
case 'b':
case 'B':
consCount(input_string);
break;
case 'c':
case 'C':
cons_and_vowelCount(input_string);
break;
case 'd':
case 'D':
newString(input_string, LENGTH);
break;
case 'e':
case 'E':
exit(0);
default:
cout << endl << "Error: '" << choice << "' is an invalid selection" << endl;
break;
} //close switch
} //close do
while (not_done);
return 0;
} // close main
/* Function printmenu()
* Input:
* none
* Process:
* Prints the menu of query choices
* Output:
* Prints the menu of query choices
*/
void printmenu(void)
{
cout << endl << endl;
cout << "A) Count the number of vowels in the string" << endl;
cout << "B) Count the number of consonants in the string" << endl;
cout << "C) Count both the vowels and consonants in the string" << endl;
cout << "D) Enter another string" << endl;
cout << "E) Exit the program" << endl;
cout << endl << "Enter your selection: ";
return;
}
int vowelCount(char *str) {
char vowels[11] = "aeiouAEIOU";
int vowel_count = 0;
for (int i = 0; i < strlen(str); i++) {
for (int j = 0; j < strlen(vowels); j++) {
if (str[i] == vowels[j]) {
vowel_count++;
}
}
}
cout << "String contains " << vowel_count << " vowels" << endl;
return vowel_count;
} // close vowelCount
int consCount(char *str) {
char cons[43] = "bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ";
int cons_count = 0;
for (int i = 0; i < strlen(str); i ++) {
for (int j = 0; j < strlen(cons); j++) {
if (str[i] == cons[j]) {
cons_count++;
}
}
}
cout << "String contains " << cons_count << " consonants" << endl;
return cons_count;
} // close consCount
int cons_and_vowelCount(char *str) {
int cons = consCount(str);
int vowels = vowelCount(str);
int total = cons + vowels;
cout << "The string contains a total of " << total << " vowels and "
"consonants" << endl;
return total;
}
void newString(char *str, int len) {
cout << "Enter a string of no more than " << len-1 << " characters:\n";
cin.getline(str, len);
return;
}