6

我有一些代码可以将视频文件上传到 YouTube：

$yt = new Zend_Gdata_YouTube($httpClient);

// create a new VideoEntry object
$myVideoEntry = new Zend_Gdata_YouTube_VideoEntry();

// create a new Zend_Gdata_App_MediaFileSource object
$filesource = $yt->newMediaFileSource('file.mov');
$filesource->setContentType('video/quicktime');
// set slug header
$filesource->setSlug('file.mov');

我在 S3 中有视频，我想将它们上传到 YouTube。我们 S3 帐户中的视频是公开的，所以我可以使用 wget 之类的命令。在运行此脚本 ( ) 之前，我是否应该运行 wgets 视频文件并将其下载到本地的命令shell_exec("wget ".$s3videoURL)？

还是我应该尝试输入 MediaFileSource 作为 S3 文件本身的 URL？

主要是，我只需要稳定性（不是经常超时的解决方案）；速度和本地存储并不重要（上传后我可以在本地删除视频文件）。

解决此问题的最佳方法是什么？

谢谢！

更新：我可能应该提到这个脚本每次执行将上传大约 5 个视频到 YouTube。

4

4 回答 4

9

这是一个老问题，但我相信我有更好的答案。

您不必将视频写入 HDD，也不能将整个内容保存在 RAM 中（我认为它是一个大文件）。

您可以使用 PHP AWS SDK 和 Google 客户端库从 S3 缓冲文件并将其发送到 YouTube。使用 registerStreamWrapper 方法将 S3 注册为文件系统并使用来自 YouTube API 的可恢复上传。然后，您所要做的就是使用 fread 从 S3 读取块并将它们发送到 YouTube。这样，您甚至可以限制 RAM 的使用。

我假设您从 Google_Video 类创建了视频对象（代码中的 $video）。这是一个完整的代码。

<?php
require_once 'path/to/libraries/aws/vendor/autoload.php';
require_once 'path/to/libraries/google-client-lib/autoload.php';

use Aws\S3\S3Client;

$chunkSizeBytes = 2 * 1024 * 1024; // 2 mb
$streamName = 's3://bucketname/video.mp4';

$s3client = S3Client::factory(array(
                    'key'    => S3_ACCESS_KEY,
                    'secret' => S3_SECRET_KEY,
                    'region' => 'eu-west-1' // if you need to set.
                ));
$s3client->registerStreamWrapper();

$client = new Google_Client();
$client->setClientId(YOUTUBE_CLIENT_ID);
$client->setClientSecret(YOUTUBE_CLIENT_SECRET);
$client->setAccessToken(YOUTUBE_TOKEN);

$youtube = new Google_YoutubeService($client);
$media = new Google_MediaFileUpload('video/*', null, true, $chunkSizeBytes);

$filesize = filesize($streamName); // use it as a reguler file.
$media->setFileSize($filesize);

$insertResponse = $youtube->videos->insert("status,snippet", $video, array('mediaUpload' => $media));
$uploadStatus = false;

$handle = fopen($streamName, "r");
$totalReceived = 0;
$chunkBuffer = '';
while (!$uploadStatus && !feof($handle)) {
    $chunk = fread($handle, $chunkSizeBytes);
    $chunkBuffer .= $chunk;
    $chunkBufferSize = strlen($chunkBuffer);
    if($chunkBufferSize > $chunkSizeBytes) {
        $fullChunk = substr($chunkBuffer, 0, $chunkSizeBytes);
        $leapChunk = substr($chunkBuffer, $chunkSizeBytes);
        $uploadStatus = $media->nextChunk($insertResponse, $fullChunk);
        $totalSend += strlen($fullChunk);

        $chunkBuffer = $leapChunk;
        echo PHP_EOL.'Status: '.($totalReceived).' / '.$filesize.' (%'.(($totalReceived / $filesize) * 100).')'.PHP_EOL;
    }

    $totalReceived += strlen($chunk);
}

$extraChunkLen = strlen($chunkBuffer);
$uploadStatus = $media->nextChunk($insertResponse, $chunkBuffer);
$totalSend += strlen($chunkBuffer);
fclose($handle);
于 2013-12-10T22:38:15.113 回答
2

“MediaFileSource”必须是真实文件。它不需要 URL，因此您需要先将视频从 S3 复制到您的服务器，然后再将它们发送到 YouTube。

如果您的使用量很少，您可能可以使用“shell_exec”，但由于各种原因，使用Zend S3 Service或cURL从 S3 提取文件可能更好。

于 2012-04-12T13:15:41.763 回答
1

我必须对@previous_developer 的答案进行一些更改，以使其与 Youtube Data API V3 一起使用（请支持他，因为除了他的之外我找不到任何工作代码）。

$streamName = 's3://BUCKET-NAME/VIDEO.mp4';


/**
Since I have been using Yii 2. Use the AWS 
SDK directly instead.
*/

    $aws = Yii::$app->awssdk->getAwsSdk();
    $s3client = $aws->createS3();


    $s3client->registerStreamWrapper();


    $service = new \Google_Service_YouTube($client);

    $snippet = new \Google_Service_YouTube_VideoSnippet();
    $snippet->setTitle("Test title");
    $snippet->setDescription("Test descrition");
    $snippet->setTags(array("tag1","tag2"));
    $snippet->setCategoryId("22");

    $status = new \Google_Service_YouTube_VideoStatus();
    $status->privacyStatus = "public";

    $video = new \Google_Service_YouTube_Video();
    $video->setSnippet($snippet);
    $video->setStatus($status);

    $client->setDefer(true);
    $insertResponse = $service->videos->insert("status,snippet", $video);


    $media = new MediaFileUpload(
        $client,
        $insertResponse,
        'video/*',
        null,
        true,
        false
    );

    $filesize = filesize($streamName); // use it as a reguler file.
    $media->setFileSize($filesize);


    $chunkSizeBytes = 2 * 1024 * 1024; // 2 mb

    $uploadStatus = false;

    $handle = fopen($streamName, "r");
    $totalSend = 0;
    $totalReceived = 0;
    $chunkBuffer = '';
    while (!$uploadStatus && !feof($handle)) {
        $chunk = fread($handle, $chunkSizeBytes);
        $chunkBuffer .= $chunk;
        $chunkBufferSize = strlen($chunkBuffer);
        if($chunkBufferSize > $chunkSizeBytes) {
            $fullChunk = substr($chunkBuffer, 0, $chunkSizeBytes);
            $leapChunk = substr($chunkBuffer, $chunkSizeBytes);
            $uploadStatus = $media->nextChunk($fullChunk);
            $totalSend += strlen($fullChunk);

            $chunkBuffer = $leapChunk;
            echo PHP_EOL.'Status: '.($totalReceived).' / '.$filesize.' (%'.(($totalReceived / $filesize) * 100).')'.PHP_EOL;
        }

        $totalReceived += strlen($chunk);
    }

    $extraChunkLen = strlen($chunkBuffer);
    $uploadStatus = $media->nextChunk($chunkBuffer);
    $totalSend += strlen($chunkBuffer);
    fclose($handle);



    // If you want to make other calls after the file upload, set setDefer back to false
    $client->setDefer(false);
于 2020-11-05T19:39:29.093 回答
-1

$chunkSizeBytes = 2 * 1024 * 1024; // 2 兆

    $s3client = $this->c_aws->getS3Client();
    $s3client->registerStreamWrapper();

    try {

        $client = new \Google_Client();

        $client->setAccessType("offline");
        $client->setApprovalPrompt('force');

        $client->setClientId(GOOGLE_CLIENT_ID);
        $client->setClientSecret(GOOGLE_CLIENT_SECRET);
        $token = $client->fetchAccessTokenWithRefreshToken(GOOGLE_REFRESH_TOKEN);


        $client->setAccessToken($token);

        $youtube = new \Google_Service_YouTube($client);

        // Create a snippet with title, description, tags and category ID
        // Create an asset resource and set its snippet metadata and type.
        // This example sets the video's title, description, keyword tags, and
        // video category.
        $snippet = new \Google_Service_YouTube_VideoSnippet();
        $snippet->setTitle($title);
        $snippet->setDescription($summary);
        $snippet->setTags(explode(',', $keywords));

        // Numeric video category. See
        // https://developers.google.com/youtube/v3/docs/videoCategories/list

// $snippet->setCategoryId("22");

        // Set the video's status to "public". Valid statuses are "public",
        // "private" and "unlisted".
        $status = new \Google_Service_YouTube_VideoStatus();
        $status->privacyStatus = "public";


        // Associate the snippet and status objects with a new video resource.
        $video = new \Google_Service_YouTube_Video();
        $video->setSnippet($snippet);
        $video->setStatus($status);

        // Setting the defer flag to true tells the client to return a request which can be called
        // with ->execute(); instead of making the API call immediately.
        $client->setDefer(true);

        $insertRequest = $youtube->videos->insert("status,snippet", $video);

        $media = new \Google_Http_MediaFileUpload(
            $client,
            $insertRequest,
            'video/*',
            null,
            true,
            $chunkSizeBytes
        );

        $result = $this->c_aws->getAwsFile($aws_file_path);

        $media->setFileSize($result['ContentLength']);

        $uploadStatus = false;

        // Seek to the beginning of the stream
        $result['Body']->rewind();

        // Read the body off of the underlying stream in chunks
        while (!$uploadStatus && $data = $result['Body']->read($chunkSizeBytes)) {

            $uploadStatus = $media->nextChunk($data);

        }
        $client->setDefer(false);
        if ($uploadStatus->status['uploadStatus'] == 'uploaded') {
            // Actions to perform for a successful upload
             $uploaded_video_id = $uploadStatus['id'];
            return ($uploadStatus['id']);
        }
    }catch (\Google_Service_Exception $exception){
        return '';
        print_r($exception);
    }
于 2017-04-07T11:37:58.077 回答