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如何在下面的 json 响应中解析它。我正在开发一个预订应用程序。我从服务器得到的响应是

 {"HotelInformationResponse": {
 "@hotelId": "210985",
  "customerSessionId": "0ABAA826-9AAF-5791-3692-A03326791310",
 "HotelSummary": {
   "@order": "0",
  "hotelId": 210985,
  "name": "Seattle Marriott Waterfront",
  "address1": "2100 Alaskan Way",
  "city": "Seattle",
  "stateProvinceCode": "WA",
  "postalCode": 98121,
  "countryCode": "US",
  "propertyCategory": 1,
  "hotelRating": 4,
  "tripAdvisorRating": 4,
  "locationDescription": "Near Seattle Aquarium",
  "highRate": 645,
  "lowRate": 279,
  "latitude": 47.61016,
  "longitude": -122.34651
},
"HotelDetails": {
  "numberOfRooms": 358,
  "numberOfFloors": 8,
  "checkInTime": "4:00 PM",
  "checkOutTime": "12:00 PM",
  "propertyInformation": "Pets not allowed   Check-in time starts at 4 PM  Check-out  time is Noon  ",
   }

任何方法都值得赞赏

4

4 回答 4

1

我希望这段代码可以帮助你

 public static String Profile_response(String response){
            try{
                JSONArray jsonarray = new JSONArray("["+response+"]");
                JSONObject jsonobject = jsonarray.getJSONObject(0);
                parseForcitydetail1(jsonobject.getString("HotelInformationResponse"));


                return response;

            }catch (Exception e) {
                return "\"" + "Access Denied" + "\"";
            }
        }

    public static void parseForcitydetail1(String res){
            try{
                 JSONArray jsonarray1 = new JSONArray(res);
                for(int i=0;i<jsonarray1.length();i++){
                        JSONObject jsonobject = jsonarray1.getJSONObject(i);
                        Hotal_ID.add(jsonobject.getString("@hotelId"));
                        customer_ID.add(jsonobject.getString("customerSessionId"));

            }
 parseForcitydetail2(jsonobject.getString("HotelSummary"));


            }catch (Exception e) {
                System.out.println(e.toString());
            }
        }

    public static void parseForcitydetail2(String res){
            try{
                 JSONArray jsonarray1 = new JSONArray(res);
                for(int i=0;i<jsonarray1.length();i++){
                        JSONObject jsonobject = jsonarray1.getJSONObject(i);
                        Order.add(jsonobject.getString("@order"));
                        hote_ID.add(jsonobject.getString("hotelId"));
    Name.add(jsonobject.getString("name"));                     Address.add(jsonobject.getString("address1"));....
    City.add(jsonobject.getString("city"));
    StateProvinceCode.add(jsonobject.getString("stateProvinceCode")); PostalCode.add(jsonobject.getString("postalCode"));
    CountryCode.add(jsonobject.getString("countryCode"));
    PropertyCategory.add(jsonobject.getString("propertyCategory"));                     HotelRating.add(jsonobject.getString("hotelRating"));....
    TripAdvisorRating.add(jsonobject.getString("tripAdvisorRating"));
    LocationDescription.add(jsonobject.getString("locationDescription")); Latitude.add(jsonobject.getString("latitude"));
    Longitude.add(jsonobject.getString("longitude"));
            }

            }catch (Exception e) {
                System.out.println(e.toString());
            }
        }

与“HotelDetails”解析相同的过程

享受 ！

于 2012-04-10T12:14:31.147 回答
0 
Using JSONOBject, JSONArray to contain data like JSONObject, JSONArray
Using methods like: getJSONObject(), getString(), getXXX(). . to get data which you want.
with XXX -  data type like int, string

您将通过描述如何清晰解析 JSON 的链接（示例）轻松了解如何在 Android 中解析 JSON： http ://www.technotalkative.com/android-json-parsing/

于 2012-04-10T13:04:31.800 回答
0

您可以使用 JSONArray 和 JSONObject 手动解析它。但它很无聊，并且在循环运行时可能需要特别注意按键。最简单且强烈推荐的方法是使用Google Gson库自动处理此问题。

于 2012-04-10T11:55:10.657 回答
0 
private JSONObject jObject;
jObject = new JSONObject(your response as string);
//this will give you json object for HotelInformationResponse
JSONObject menuObject = jObject.getJSONObject("HotelInformationResponse");
by this way you can get values
String hotelId = menuObject.getString("@hotelId");
String customerSessionId = menuObject.getString("customerSessionId");
//...rest are same do same thing for HotelDetails

欲了解更多信息，请查看此链接

于 2012-04-10T12:00:51.707 回答