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我正在尝试制作一个相当基本的 3D 游戏,为我参加 Ludum Dare 23 一年一度的游戏比赛做准备。

我正在使用 Java,我正在使用 Swing 和 AWT。(我正在使用 JFrame 来创建我的窗口(显然?idk))

当我尝试在屏幕上绘制像素时,我遇到的问题正在发生。我得到了一些关于BufferStrategy显然是线程问题的例外情况。

以下是 Eclipse 中的控制台框向我抛出的内容。

Exception in thread "Thread-2" java.lang.IllegalStateException: Component must have a valid peer
    at java.awt.Component$FlipBufferStrategy.createBuffers(Component.java:3982)
    at java.awt.Component$FlipBufferStrategy.<init>(Component.java:3956)
    at java.awt.Component$FlipSubRegionBufferStrategy.<init>(Component.java:4479)
    at java.awt.Component.createBufferStrategy(Component.java:3833)
    at java.awt.Canvas.createBufferStrategy(Canvas.java:194)
    at java.awt.Component.createBufferStrategy(Component.java:3756)
    at java.awt.Canvas.createBufferStrategy(Canvas.java:169)
    at com.ottdev.tale.TaleOfDwarvesComponent.render(TaleOfDwarvesComponent.java:66)
    at com.ottdev.tale.TaleOfDwarvesComponent.run(TaleOfDwarvesComponent.java:55)
    at java.lang.Thread.run(Thread.java:722)

关于如何解决这个问题的任何想法?它正在使我陷入困境并阻止我前进。非常感谢所有帮助!

PS:如果需要,我可以提供我的源代码,但现在,我宁愿知道如何修复它,以便我知道如果将来遇到这种情况该怎么办,但使用不同的代码。

编辑:我的主要课程 - TaleOfDwarvesComponent:

package com.ottdev.tale;    
import java.awt.*;
import java.awt.image.*;

import javax.swing.*;

import com.ottdev.tale.gui.*;

public class TaleOfDwarvesComponent extends Canvas implements Runnable {
    public static final int WIDTH = 800;
    public static final int HEIGHT = 600;
    public static final int SCALE = 2;
    public static final String TITLE = "Tale Of Dwarves!";

    private boolean running = false;
    private BufferedImage img;
    public int[] pixels;
    private Thread thread;
    private Game game;
    private Screen screen;

    public TaleOfDwarvesComponent() {
        game = new Game();
        screen = new Screen(WIDTH, HEIGHT);

        img = new BufferedImage(WIDTH, HEIGHT, BufferedImage.TYPE_INT_RGB);
        pixels = ((DataBufferInt) img.getRaster().getDataBuffer()).getData();



    }

    public void start() {
        if (running)
            return;
        running = true;
        new Thread(this).start();
    }

    public void stop() {
        if (!running)
            return;
        running = false;
        try{
            thread.join();
        }catch(InterruptedException e){
            e.printStackTrace();
        }

    }

    public void run() {
        while(running){
            render();
        }
    }

    public void tick(){
        game.tick();
    }

    public void render(){

        BufferStrategy bs = getBufferStrategy();
        if(bs == null){
            createBufferStrategy(3);
            return;
        }
        screen.render(game);
        for (int i = 0; i < WIDTH * HEIGHT; i++){
            pixels[i] = screen.pixels[i];
        }

        Graphics g = bs.getDrawGraphics();
        g.fillRect(0, 0, getWidth(), getHeight());
        g.drawImage(img, 0, 0, WIDTH * SCALE, HEIGHT * SCALE, null);
        g.dispose();
        bs.show();
    }

    public static void main(String[] args) {
        TaleOfDwarvesComponent game = new TaleOfDwarvesComponent();
        JFrame frame = new JFrame();
        frame.setSize(WIDTH, HEIGHT);
        frame.setLocationRelativeTo(null);
        frame.setTitle(TITLE);
        frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
        frame.setVisible(true);

        game.start();

    }
}

我有一个Bitmap班级和一个Screen班级,但现在,我会提出这个,希望可以从中获得解决我的烦恼的答案。

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1 回答 1

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如果您查看 javadocs http://docs.oracle.com/javase/7/docs/api/java/awt/Canvas.html#createBufferStrategy(int )

我相信它专门解决了您的问题,即您在 Canvas 显示在屏幕上之前调用 createBufferStrategy 。因此,要解决您的问题,您需要向 Canvas 添加一个 ComponentListener 并在 componentShown 上调用 createBufferStrategy,或者在您的绘制方法中调用它

于 2012-04-09T19:36:16.027 回答