我需要发送带有 JSON 数据的 POST 方法,确保我需要发送序列化为字符串的 JSON 对象。不是 JSON 字符串本身。所以我如何使用 JAVA 实现它
问问题
4053 次
3 回答
1
public static String sendPostRequest(String postURL) throws Exception{
String responseStr=null;
//make POST request
String jsonContent = "{'name': 'newIndia','columns': [{'name': 'Species','type': 'STRING'}],'description': 'Insect Tracking Information.','isExportable': true}";
//String data = "{\"document\" : {\"_id\": \"" + id+ "\", \"context\":" + context +"}}";
URL url = new URL(postURL);
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.setDoOutput(true);
connection.setDoInput(true);
connection.setInstanceFollowRedirects(false);
connection.setRequestMethod("POST");
connection.setRequestProperty("Content-Type", "application/json");
connection.setRequestProperty("charset", "utf-8");
connection.setRequestProperty("Content-Length", "" + Integer.toString(jsonContent.getBytes().length));
connection.setUseCaches(false);
OutputStreamWriter writer = new OutputStreamWriter(connection.getOutputStream(), "UTF-8");
writer.write(jsonContent);
writer.close();
responseStr="Response code: "+connection.getResponseCode()+" and mesg:"+connection.getResponseMessage();
System.out.println(connection.getResponseMessage());
InputStream response;
// Check for error , if none store response
if(connection.getResponseCode() == 200){
response = connection.getInputStream();
}else{
response = connection.getErrorStream();
}
InputStreamReader isr = new InputStreamReader(response);
StringBuilder sb = new StringBuilder();
BufferedReader br = new BufferedReader(isr);
String read = br.readLine();
while(read != null){
sb.append(read);
read = br.readLine();
}
// Print the String
System.out.println(sb.toString());
connection.disconnect();
return responseStr;
}
有关更多信息,您可以查看此示例。
于 2013-12-24T14:14:18.807 回答
0
使用gson,您可以非常轻松地将 JSON 数据发布到 Web 服务。
例如:
public class MyData { //var myJsonData = {
private boolean fans = true; // fans:true,
private boolean funds = true; // funds:true
//private String chart = "day"; // }
}
现在将 POJO 发送到真正的Web 服务:
public class Main {
public static void main(String... args) throws Exception {
URL theUrl = new URL("https://robertsspaceindustries.com/api/stats/getCrowdfundStats");
Gson gson = new Gson();
JsonParser jp = new JsonParser();
MyData thedata = new MyData();
HttpsURLConnection urlConnection = (HttpsURLConnection) theUrl.openConnection();
urlConnection.setRequestMethod("POST");
urlConnection.setDoOutput(true); //allow parameters to be sent/appended
DataOutputStream wr = new DataOutputStream(urlConnection.getOutputStream());
wr.writeBytes(gson.toJson(thedata)); //convert the POJO to JSON, then to binary.
wr.flush();
wr.close();
urlConnection.connect(); //start request transmission
JsonElement retJson = jp.parse(new InputStreamReader((InputStream) urlConnection.getContent())); //convert the input stream to a json element
System.out.println(retJson.getAsJsonObject());
urlConnection.disconnect(); //end request transmission
}
}
回复:
{"success":1,"{"fans":910125,"funds":8410319141},"code":"OK","msg":"OK"}
(注意,在撰写本文时等效的 cURL 命令是)->
curl 'https://robertsspaceindustries.com/api/stats/getCrowdfundStats' --data-binary '{"fans":true,"funds":true}'
于 2015-06-15T08:19:50.143 回答