c# - 迟到查询语法

Question

我正在尝试了解员工迟到的频率

到目前为止我用过这个

SELECT  EMPID 
       ,EMPNAME
      ,COUNT(TimeIn) AS LATECOUNT  FROM        
 (SELECT  EMPLOYEEID AS EMPID, EmployeeName AS EMPNAME, AbsenceDate AS ABSDAT, MIN(TimeIn) AS TimeIn
   FROM  dbo.viewAttendance
         GROUP BY AbsenceDate, EMPLOYEEID, EmployeeName
         HAVING      (MIN(TimeIn) > '08:00:00')
  ) AS a

使用该代码，我只能检索只有至少一名迟到的员工的行（仅返回 30 行）。我真正想要的是 300 行（所有员工）的完整回报，显示他们的迟到数量。我的头脑不够清晰，无法找到正确的语法。我知道问题出在 HAVING (MIN(timeIn) > '08:00:00' 有人可以帮助我吗？提前谢谢... :)

Answer 1

SELECT
  E.EMPNAME
  ISNULL(SUM(CASE WHEN A.TIMEIN > '08:00:00' THEN 1 ELSE 0 END), 0) AS LATE_ATTENDANCE
FROM
 dbo.MASTEREMPLOYEE E
 LEFT JOIN dbo.viewATTENDANCE A ON A.EMPLOYEEID = E.EMPLOYEEID

Answer 2

你为什么不使用这样的东西：

select e.empname, (select count(1) from dbo.viewAttendance a where a.EmployeeId = e.employeeId and a.timein > '08:00:00') as latecount
from employees e