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我正在尝试使用 webapp 构建应用程序Spring MVC并Maven 3.0在Eclipse其中使用 webapp。我无法进入初始页面，也无法从那里导航到任何其他页面而没有404 error. 如果有什么我遗漏的，请告诉我。谢谢！

mvc-dispatcher.xml

    <?xml version="1.0" encoding="UTF-8"?><beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context"
xmlns:jdbc="http://www.springframework.org/schema/jdbc" xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="http://www.springframework.org/schema/beans 
    http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
    http://www.springframework.org/schema/context 
    http://www.springframework.org/schema/context/spring-context-3.0.xsd
    http://www.springframework.org/schema/jdbc
    http://www.springframework.org/schema/jdbc/spring-jdbc-3.0.xsd
    http://www.springframework.org/schema/mvc 
    http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd">

<context:component-scan base-package="se.guards.controller" />
<mvc:resources mapping="/resources/**" location="/resources/" />
<mvc:annotation-driven />
<context:annotation-config />


<!-- show pictures -->
<mvc:default-servlet-handler />

<!-- also add the following beans to get rid of some exceptions -->
<bean
    class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter" />
<bean
    class="org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping">
</bean>
<bean
    class="org.springframework.web.servlet.view.InternalResourceViewResolver">
    <property name="viewClass"
        value="org.springframework.web.servlet.view.JstlView" />
    <property name="prefix" value="/WEB-INF/views/" />
    <property name="suffix" value=".jsp" />
</bean>

<bean id="messageSource"
    class="org.springframework.context.support.ResourceBundleMessageSource">
    <property name="basenames">
        <list>
            <value>mymessages</value>
        </list>
    </property>
</bean>

web.xml

<web-app id="WebApp_ID" version="2.4"
xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee 
http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">

<display-name>Spring MVC Application</display-name>

<!-- Spring MVC -->
<servlet>
    <servlet-name>mvc-dispatcher</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <load-on-startup>1</load-on-startup>
</servlet>

<servlet-mapping>
    <servlet-name>mvc-dispatcher</servlet-name>
    <url-pattern>/</url-pattern>
</servlet-mapping>

<listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>

<servlet>
    <servlet-name>>mvc-dispatcher</servlet-name>
    <servlet-class>org.springframework.js.resource.ResourceServlet</servlet-class>
    <load-on-startup>1</load-on-startup>
</servlet>

<context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>
        /WEB-INF/mvc-dispatcher-servlet.xml,
        /WEB-INF/spring-database.xml,
    </param-value>
</context-param>

<!-- Spring Security -->
<filter>
    <filter-name>springSecurityFilterChain</filter-name>
    <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>

<filter-mapping>
    <filter-name>springSecurityFilterChain</filter-name>
    <url-pattern>/*</url-pattern>
</filter-mapping>

数据库.xml

<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd">

<bean id="dataSource"
    class="org.springframework.jdbc.datasource.DriverManagerDataSource">

    <property name="driverClassName" value="com.mysql.jdbc.Driver" />
    <property name="url" value="jdbc:mysql://localhost:3306/test" />
    <property name="username" value="root" />
    <property name="password" value="password" />
</bean>

用户控制器.java

    package se.guards.controller;
    import java.util.ArrayList;
    import java.util.Collection;
    import org.springframework.beans.factory.annotation.Autowired;
    import org.springframework.stereotype.Controller;
    import org.springframework.ui.Model;
    import org.springframework.web.bind.annotation.RequestMapping;
    import org.springframework.web.bind.annotation.RequestMethod;
    import se.datalayer.guards.service.UserService;
    import se.guard.User;

    @Controller
    @RequestMapping(value="/")
    public class UserController
    {

@SuppressWarnings("unused")
@Autowired
private UserService userService;

@RequestMapping(value = "/", method = RequestMethod.GET)
public String findAllUsers(Model model){

    Collection<User> userList= new ArrayList<User>();

    model.addAttribute("users", userList);
    return "showallusers";

        }

       }

showallusers.jsp

 <%@ page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
 <%@ taglib prefix="c" uri="http://java.sun.com/jsp/jstl/core"%>
<%@ taglib uri="http://java.sun.com/jsp/jstl/fmt" prefix="fmt"%>
<%@ taglib prefix="form" uri="http://www.springframework.org/tags/form"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4 /loose.dtd">
  <html>
 <head>
 <meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
 <title>found users</title>
</head>
<body>
<table>
    <c:forEach var="allusers" items="${users}">
        <tr>
            <td>${allusers.firstname}</td>

            <td>${allusers.lastname}</td>
        </tr>
    </c:forEach>
        </table>
     </body>
    </html>

回答问题：

这是我正在使用的代码。@Controller 注释必须存在。正如我之前所说，我得到： HTTP 状态 404 - /guard_weblayer/ 类型状态报告消息 /guard_weblayer/ 描述 请求的资源 (/guard_weblayer/) 不可用。Apache Tomcat/7.0.25

我使用restfule 设计、domainlayer、datalayer 和weblayer。它会影响网络播放器吗？

4

1 回答 1

0

您可能想重新开始并使用springbyexample中的示例。它以一种可以理解的方式包含了你需要的一切（在 Maven 中也是如此。）

这很可能比调试当前代码更容易。

于 2012-04-09T06:27:44.540 回答