javascript - 向除发件人以外的所有客户端发送响应

Question

要将某些内容发送给所有客户端，请使用：

io.sockets.emit('response', data);

要从客户那里接收，您使用：

socket.on('cursor', function(data) {
  ...
});

如何将两者结合起来，以便在服务器上从客户端接收消息时，将该消息发送给除发送消息的用户之外的所有用户？

socket.on('cursor', function(data) {
  io.sockets.emit('response', data);
});

我是否必须通过发送带有消息的客户端 ID 然后检查客户端来破解它，还是有更简单的方法？

score 927 · Accepted Answer

这是我的清单（针对 1.0 更新）：

// sending to sender-client only
socket.emit('message', "this is a test");

// sending to all clients, include sender
io.emit('message', "this is a test");

// sending to all clients except sender
socket.broadcast.emit('message', "this is a test");

// sending to all clients in 'game' room(channel) except sender
socket.broadcast.to('game').emit('message', 'nice game');

// sending to all clients in 'game' room(channel), include sender
io.in('game').emit('message', 'cool game');

// sending to sender client, only if they are in 'game' room(channel)
socket.to('game').emit('message', 'enjoy the game');

// sending to all clients in namespace 'myNamespace', include sender
io.of('myNamespace').emit('message', 'gg');

// sending to individual socketid
socket.broadcast.to(socketid).emit('message', 'for your eyes only');

// list socketid
for (var socketid in io.sockets.sockets) {}
 OR
Object.keys(io.sockets.sockets).forEach((socketid) => {});

score 44 · Accepted Answer

来自@LearnRPG 的答案，但使用 1.0：

 // send to current request socket client
 socket.emit('message', "this is a test");

 // sending to all clients, include sender
 io.sockets.emit('message', "this is a test"); //still works
 //or
 io.emit('message', 'this is a test');

 // sending to all clients except sender
 socket.broadcast.emit('message', "this is a test");

 // sending to all clients in 'game' room(channel) except sender
 socket.broadcast.to('game').emit('message', 'nice game');

 // sending to all clients in 'game' room(channel), include sender
 // docs says "simply use to or in when broadcasting or emitting"
 io.in('game').emit('message', 'cool game');

 // sending to individual socketid, socketid is like a room
 socket.broadcast.to(socketid).emit('message', 'for your eyes only');

要回答@Crashalot 评论，socketid来自：

var io = require('socket.io')(server);
io.on('connection', function(socket) { console.log(socket.id); })

score 13 · Accepted Answer

这是关于从 0.9.x 到 1.x 发生了什么变化的更完整的答案。

 // send to current request socket client
 socket.emit('message', "this is a test");// Hasn't changed

 // sending to all clients, include sender
 io.sockets.emit('message', "this is a test"); // Old way, still compatible
 io.emit('message', 'this is a test');// New way, works only in 1.x

 // sending to all clients except sender
 socket.broadcast.emit('message', "this is a test");// Hasn't changed

 // sending to all clients in 'game' room(channel) except sender
 socket.broadcast.to('game').emit('message', 'nice game');// Hasn't changed

 // sending to all clients in 'game' room(channel), include sender
 io.sockets.in('game').emit('message', 'cool game');// Old way, DOES NOT WORK ANYMORE
 io.in('game').emit('message', 'cool game');// New way
 io.to('game').emit('message', 'cool game');// New way, "in" or "to" are the exact same: "And then simply use to or in (they are the same) when broadcasting or emitting:" from http://socket.io/docs/rooms-and-namespaces/

 // sending to individual socketid, socketid is like a room
 io.sockets.socket(socketid).emit('message', 'for your eyes only');// Old way, DOES NOT WORK ANYMORE
 socket.broadcast.to(socketid).emit('message', 'for your eyes only');// New way

我想编辑@soyuka 的帖子，但我的编辑被同行评审拒绝了。

score 8 · Accepted Answer

发出备忘单

io.on('connect', onConnect);

function onConnect(socket){

  // sending to the client
  socket.emit('hello', 'can you hear me?', 1, 2, 'abc');

  // sending to all clients except sender
  socket.broadcast.emit('broadcast', 'hello friends!');

  // sending to all clients in 'game' room except sender
  socket.to('game').emit('nice game', "let's play a game");

  // sending to all clients in 'game1' and/or in 'game2' room, except sender
  socket.to('game1').to('game2').emit('nice game', "let's play a game (too)");

  // sending to all clients in 'game' room, including sender
  io.in('game').emit('big-announcement', 'the game will start soon');

  // sending to all clients in namespace 'myNamespace', including sender
  io.of('myNamespace').emit('bigger-announcement', 'the tournament will start soon');

  // sending to individual socketid (private message)
  socket.to(<socketid>).emit('hey', 'I just met you');

  // sending with acknowledgement
  socket.emit('question', 'do you think so?', function (answer) {});

  // sending without compression
  socket.compress(false).emit('uncompressed', "that's rough");

  // sending a message that might be dropped if the client is not ready to receive messages
  socket.volatile.emit('maybe', 'do you really need it?');

  // sending to all clients on this node (when using multiple nodes)
  io.local.emit('hi', 'my lovely babies');

};

score 7 · Accepted Answer

broadcast.emit 将 msg 发送给所有其他客户端（发送者除外）

socket.on('cursor', function(data) {
  socket.broadcast.emit('msg', data);
});

score 4 · Accepted Answer

For namespaces within rooms looping the list of clients in a room (similar to Nav's answer) is one of only two approaches I've found that will work. The other is to use exclude. E.G.

socket.on('message',function(data) {
    io.of( 'namespace' ).in( data.roomID ).except( socket.id ).emit('message',data);
}

score 1 · Accepted Answer

其他案例

io.of('/chat').on('connection', function (socket) {
    //sending to all clients in 'room' and you
    io.of('/chat').in('room').emit('message', "data");
};

score 1 · Accepted Answer

为 Socket.io v4.0.0+ 更新

要在 v4 中向除发件人之外的所有客户端发出，请使用：

socket.broadcast.emit(/* ... */);

示例用法

io.on("connection", (socket) => {
   socket.on("message", (message) => {
      //sends "newMessage" to all sockets except sender
      socket.broadcast.emit("newMessage", message)
   })
})

score 1 · Accepted Answer

更新了列表以获取更多文档。

socket.emit('message', "this is a test"); //sending to sender-client only
socket.broadcast.emit('message', "this is a test"); //sending to all clients except sender
socket.broadcast.to('game').emit('message', 'nice game'); //sending to all clients in 'game' room(channel) except sender
socket.to('game').emit('message', 'enjoy the game'); //sending to sender client, only if they are in 'game' room(channel)
socket.broadcast.to(socketid).emit('message', 'for your eyes only'); //sending to individual socketid
io.emit('message', "this is a test"); //sending to all clients, include sender
io.in('game').emit('message', 'cool game'); //sending to all clients in 'game' room(channel), include sender
io.of('myNamespace').emit('message', 'gg'); //sending to all clients in namespace 'myNamespace', include sender
socket.emit(); //send to all connected clients
socket.broadcast.emit(); //send to all connected clients except the one that sent the message
socket.on(); //event listener, can be called on client to execute on server
io.sockets.socket(); //for emiting to specific clients
io.sockets.emit(); //send to all connected clients (same as socket.emit)
io.sockets.on() ; //initial connection from a client.

希望这可以帮助。

score 1 · Accepted Answer

V4.x 中服务器端所有有效的发出事件列表

io.on("connection", (socket) => {

// basic emit
socket.emit(/* ... */);

// to all clients in the current namespace except the sender
socket.broadcast.emit(/* ... */);

// to all clients in room1 except the sender
socket.to("room1").emit(/* ... */);

// to all clients in room1 and/or room2 except the sender
socket.to(["room1", "room2"]).emit(/* ... */);

// to all clients in room1
io.in("room1").emit(/* ... */);

// to all clients in room1 and/or room2 except those in room3
io.to(["room1", "room2"]).except("room3").emit(/* ... */);

// to all clients in namespace "myNamespace"
io.of("myNamespace").emit(/* ... */);

// to all clients in room1 in namespace "myNamespace"
io.of("myNamespace").to("room1").emit(/* ... */);

// to individual socketid (private message)
io.to(socketId).emit(/* ... */);

// to all clients on this node (when using multiple nodes)
io.local.emit(/* ... */);

// to all connected clients
io.emit(/* ... */);

// WARNING: `socket.to(socket.id).emit()` will NOT work, as it will send to everyone in the room
// named `socket.id` but the sender. Please use the classic `socket.emit()` instead.

// with acknowledgement
socket.emit("question", (answer) => {
    // ...
});

// without compression
socket.compress(false).emit(/* ... */);

// a message that might be dropped if the low-level transport is not writable
socket.volatile.emit(/* ... */);

});

客户端

// basic emit
    socket.emit(/* ... */);

// with acknowledgement
    socket.emit("question", (answer) => {
        // ...
    });

// without compression
    socket.compress(false).emit(/* ... */);

// a message that might be dropped if the low-level transport is not writable
    socket.volatile.emit(/* ... */);

存档链接到源 => http://archive.today/2021.06.22-023900/https://socket.io/docs/v4/emit-cheatsheet/index.html

score 0 · Accepted Answer

使用这个编码

io.sockets.on('connection', function (socket) {

    socket.on('mousemove', function (data) {

        socket.broadcast.emit('moving', data);
    });

这个 socket.broadcast.emit() 将在函数中发出任何东西，除了正在发出的服务器

score 0 · Accepted Answer

我正在使用命名空间和房间 - 我发现

socket.broadcast.to('room1').emit('event', 'hi');

在哪里工作

namespace.broadcast.to('room1').emit('event', 'hi');

没有

（如果其他人面临这个问题）

javascript - 向除发件人以外的所有客户端发送响应

12 回答 12

发出备忘单

为 Socket.io v4.0.0+ 更新

要在 v4 中向除发件人之外的所有客户端发出，请使用：

V4.x 中服务器端所有有效的发出事件列表

客户端

Related

Reference