当我编译我的程序时,我得到三个“未定义的对'PrintArgv(...)'的引用”错误。我已经搜索过,但找不到出现这些错误的原因。这是我的代码:
#include "tools.hpp"
enum ARG_T {COMMAND, SWITCH, ARGUMENT};
void ReadArgs(int, char**, ofstream&);
void PrintArgv(char*, ARG_T, ofstream&);
int main(int argc, char* argv[])
{
ofstream fout;
try{
fout.open("P1Ford.txt", ios::out | ios::app);
}
catch(...)
{
//fatal("Could not open file P1Ford.txt");
cout << "Could not open file P1Ford.txt" << "\n";
return -1;
}
ReadArgs(argc, argv, fout);
fout.close();
return 0;
}
/*-----------------------------------------------------------------------------
This function takes the values passed in through the command line
then examines each one to determine if it is the command, a switch or
an argument. Then passes it to a function to print it to the file.
-----------------------------------------------------------------------------*/
void ReadArgs(int argc, char* argv[], ofstream& fout)
{
for(int c=0; c<argc; ++c)
{
if(c == 0) PrintArgv(argv[c], COMMAND, fout);
else if(strncmp(argv[c], "-", 1) == 0) PrintArgv(argv[c], SWITCH, fout);
else if(strncmp(argv[c], ">", 1) == 0) ;
else PrintArgv(argv[c], ARGUMENT, fout);
}
}
/*-----------------------------------------------------------------------------
This function prints the argument in the correct format
Command <command>
Switch <switch>
Argument <agrument>
Argument <argument>
-----------------------------------------------------------------------------*/
void PrintArgv(char* val, ARG_T type, ostream& fout)
{
if(type == COMMAND) fout << "Command " << val << "\n";
if(type == SWITCH) fout << "\t" << "Switch " << val << "\n";
if(type == ARGUMENT) fout << "\t" << "Argument " << val << "\n";
}
该功能ReadArgs
是我得到错误的地方。每次调用PrintArgv
都会给我错误。我正在使用 G++ 4.6.1。