这是我用于自定义搜索的代码,
<div id="cse-search-form" style="width: 100%;">Loading</div>
<script src="http://www.google.com.pk/jsapi" type="text/javascript"></script>
<script type="text/javascript">
google.load('search', '1', {language : 'en', style : google.loader.themes.V2_DEFAULT});
$('input[@name=sr]').change(function() {
if ($("input[@name=sr]:checked").val() == 'kw')
var qval = "kw"
else
var qval = "gw"
});
google.setOnLoadCallback(function() {
var customSearchOptions = {}; var customSearchControl = new google.search.CustomSearchControl(
'009317721292264254327:ce_olwjr2z4', customSearchOptions);
customSearchControl.setResultSetSize(google.search.Search.FILTERED_CSE_RESULTSET);
var qval = $("input[@name=sr]:checked").val();
var options = new google.search.DrawOptions();
options.setAutoComplete(true);
options.enableSearchboxOnly("http://www.alhudapk.com/audios/search.html", qval);
customSearchControl.draw('cse-search-form', options);
}, true);
</script>
<div style="margin-top: 10px;">
<input type="radio" name="sr" id="kw" value="kw" checked="checked" />Audio
<input type="radio" name="sr" id="gw" value="gw" / >Web
</div>
<style type="text/css">
input.gsc-input, .gsc-input-box, .gsc-input-box-hover, .gsc-input-box-focus {
border-color: #D9D9D9;
}
input.gsc-search-button, input.gsc-search-button:hover, input.gsc-search-button:focus {
border-color: #2F5BB7;
background-color: #357AE8;
background-image: none;
filter: none;
}
.gsc-search-box {
margin-top: -5px !important;
margin-bottom: -5px !important;
}
</style>
我只需要一个简单的结果,即
如果 radio1 被选中
search.html?kw=mysearchkeyword
如果 radio2 被选中?gw=mysearchkeyword
原因是对于“kw”,我使用的是我自己的个人搜索,而对于谷歌网络搜索,我需要“gw”参数来传递 url,请帮助
我的代码在页面加载后不起作用,它只能工作一次,但在页面加载后不会更改任何值