我的 ajax 和 php 代码又遇到了麻烦。该语句我一直未能获得成功的语句。这是我的代码
<script type="text/javascript">
$(document).ready(function(){
$("#login_a").click(function(){
$("#shadow").fadeIn("normal");
$("#login_form").fadeIn("normal");
$("#Username").focus();
});
$("#cancel_hide").click(function(){
$("#login_form").fadeOut("normal");
$("#shadow").fadeOut();
});
$("#login").click(function(){
username=$("#Username").val();
password=$("#Password").val();
$.ajax({
type: "POST",
url: "1.php",
data: "Username="+username+"&Password="+password,
success: function(html){
if(html=='1')
{ $("#login_form").fadeOut("normal");
$("#shadow").fadeOut("normal");
document.location = '/reward/home.php';
}
else
{
$("#add_err").html("Wrong Username or Password");
}
},
beforeSend:function()
{
$("#add_err").html("Loading...")
}
});
return false;
});
});
</script>
</head>
<body>
<div id="login_form">
<form action="" id="loginForm">
<label>User Name:</label>
<input type="text" id="Username" name="Username" />
<label>Password:</label>
<input type="password" id="Password" name="Password" />
<label></label><br/>
<input type="submit" id="login" value="Login" />
<input type="button" id="cancel_hide" value="Cancel" />
</form>
<div class="err" id="add_err" style="color:#FF0000; font-weight:bold"></div>
</div>
我的 SQL 连接都位于我的函数文件中。当我绕过ajax并从表单转到dologin.php时，它会回显s“1”，这应该意味着成功并让我登录。
这是我的dologin.php文件......
$root = $_SERVER['DOCUMENT_ROOT'];
include($root."/reward/function.php");
$Username = mysql_real_escape_string($_REQUEST['Username']);
$Password = mysql_real_escape_string($_REQUEST['Password']);
$Password2 = ($Password);
$sql = mysql_query("SELECT * FROM PERSON WHERE Username = '$Username' AND Password = '$Password2'") or die(mysql_error());
$sql2 = mysql_query("SELECT * FROM PERSON WHERE Username = '$Username'");
if(mysql_num_rows($sql)==1){
echo "1";
while($info = mysql_fetch_assoc($sql)){
$FName = $info['FName'];
$_SESSION['FName24'] = $FName;
}
}
elseif (mysql_num_rows($sql)>1){
echo "2";
}
elseif (mysql_num_rows($sql)==0){
echo "0";
} ?>