嘿伙计们,我正在使用 Hawkee 的这个插件。就像推特一样,您可以在其中@提及某人。我的输出有问题。这种方法:
updateHidden: function() {
var trigger = this.options.trigger;
var contents = this.element.val();
for(var key in this.id_map) {
var regex = trigger+key;
regex = regex.replace(/[!@#\$%\^&\*\(\)\+=-\[\]\\';,\.\/\{\}\|":<>\?~_]/g, '\\$&');
regex = new RegExp(regex, "g");
//contents = contents.replace(regex, trigger+'['+this.id_map[key]+']');
//I changed the code above to:
contents = contents.replace(regex, '@[' + this.id_map[key] +':' + key + ']');
}
$(this.options.hidden).val(contents);
}
上面的代码将被输出到影响其值的隐藏标签,其中
输出: @[123:peterwateber] //格式为@[]。
我使用 PHP 作为我的后端。我的问题是我想将输出转换为
<a href="www.something.com/profile?pid=123">peterwateber</a>
我对这里的代码有很大的问题,因为我不擅长 RegEx。我想出了代码:
//THIS CODE SHOULD GET 1234,peterwateber,88,hi.
$string = "@[1231:peterwateber] sdfsdfsdfsdfsdfsdf@[88:hi]sddsf";
preg_match_all("^\[(.*?)\]^",$string,$matches,PREG_PATTERN_ORDER);
foreach ($matches[1] as $match) {
echo $match.'<br/>'; //outputs 1231:peterwateber, 88:hi
}
preg_match_all("^\[([\w\d]+):(.*?)\]^",$string,$aw,PREG_PATTERN_ORDER);
foreach ($aw[1] as $match) {
echo $match.'<br/>'; //sad to say this code outputs the text '1231 and 88'
}
此外,为了能够获得输出,我有这种形式:
<form class="form-horizontal" data-post="request" method="post">
<div class="control-group boxTextAreaHolder">
<textarea placeholder="What are you thinking?" class="UITextarea" title="What are you thinking?" name="statuspost" id="statuspost" tag-status="this"></textarea>
<input type="hidden" name="tags" id="tag-post" />
</div>
</form>
提交后,输出将被处理到此函数。此函数不允许任何 htmlspecialchars 并检测类似的 url"http://stackoverflow.com"
private static function validate_text($text = '') {
// This method is used internally as a FILTER_CALLBACK
if (mb_strlen($text, 'utf8') < 1)
return false;
// Encode all html special characters (<, >, ", & .. etc) and convert
//$str = nl2br(htmlspecialchars($text));
$str = htmlspecialchars($text);
// the new line characters to <br> tags:
// Remove the new line characters that are left
$str = str_replace(array(chr(10), chr(13)), '', $str);
$text = preg_replace('#(script|about|applet|activex|chrome):#is', "\\1:", $str);
$ret = ' ' . $text;
$ret = preg_replace("#(^|[\n ])([\w]+?://[\w\#$%&~/.\-;:=,?@\[\]+]*)#is", "\\1<a href=\"\\2\" target=\"_blank\">\\2</a>", $ret);
$ret = preg_replace("#(^|[\n ])((www|ftp)\.[\w\#$%&~/.\-;:=,?@\[\]+]*)#is", "\\1<a href=\"http://\\2\" target=\"_blank\">\\2</a>", $ret);
$ret = preg_replace("#(^|[\n ])([a-z0-9&\-_.]+?)@([\w\-]+\.([\w\-\.]+\.)*[\w]+)#i", "\\1<a href=\"mailto:\\2@\\3\">\\2@\\3</a>", $ret);
//$ret = preg_replace("#^*@([)([0-9-])(])#is", "\\1<a href=\"http://\\2\" target=\"_blank\">\\2</a>", $ret);
$ret = substr($ret, 1);
return $ret;
}
现在的问题是我不知道如何将 @[1234:peterwateber] 转换为**<a href="www.something.com/profile?pid=123">peterwateber</a>**
以及如何从htmlspecialchars中排除锚标签