1

我正在创建一个查询来获取每季度的数据。

我在表中有4 个字段， 每个季度有 3 个月，user_targetquarter1quarter2quarter3quarter4

quater1 - Jan Feb March
quater2 - Apr May June
quater3 - July Aug Sept
quater4 - Oct Nov Dec

现在，当我将 $P{month} 作为 Jan、Feb 或 March 传递时，我应该得到第 1 季度的数据。同样，当我将 $P{month} 作为 Apr、May 或 June 传递时，我应该获取第 2 季度等的数据。我不想为不同的月份编写 4 个不同的查询。可以在单个查询本身中实现吗？

我对 quater1 的查询如下：

select    sum(t.quarter1) as quarter ,
          s.name as sname, f.name as fname, m.name as pname 
from user_target t, res_salesteam s, 
     account_fiscalyear f,res_users u, res_users ru, account_month m
where t.salesteam_id = s.id and 
      t.fiscal_year = f.id and  
      f.id = $P{fiscalyear} and 
      p.fiscalyear_id = f.id and 
      m.id = $P{month} and 
      u.parent_id = ru.id and 
      ru.id = $P{name} and (u.tri_salesteam = s.id or ru.tri_salesteam = u.id)
group by s.name, f.name, m.name order by s.name
4

2 回答 2

3

您可以使用CASE ... END逻辑构造

SELECT sum(CASE
    WHEN $P{month} IN ('Jan','Feb','March') THEN t.quarter1
    WHEN $P{month} IN ('Apr','May','June') THEN t.quarter2
    WHEN $P{month} IN ('July','Aug','Sept') THEN t.quarter3
    WHEN $P{month} IN ('Oct','Nov','Dec') THEN t.quarter4
    ELSE 0 END) AS quarter,
    s.name as sname, f.name as fname, m.name as pname
  FROM ...
于 2012-04-06T10:58:59.483 回答
1

使用 MYSQL 函数QUARTER()获取传递日期的季度并sum 根据返回的季度使用if /else

试试下面：

select sum(if(QUARTER(start_date)=1,t.quarter1,0)) as quarter1,
SUM(if(QUARTER(start_date)=2,t.quarter2,0)) as quarter2,
SUM((QUARTER(start_date)=3,t.quarter3,0)) as quarter3,
SUM(IF(QUARTER(start_date)=4,quarter4,0)) as quarter4,s.name as sname, f.name as fname, m.name as pname 
    from user_target t, res_salesteam s, account_fiscalyear f,res_users u, res_users ru, account_month m
    where t.salesteam_id = s.id and t.fiscal_year = f.id and  f.id = $P{fiscalyear} and p.fiscalyear_id = f.id and m.id = $P{month}
    and u.parent_id = ru.id and ru.id = $P{name} and (u.tri_salesteam = s.id or ru.tri_salesteam = u.id)
    group by s.name, f.name, m.name order by s.name
于 2012-04-06T06:57:18.823 回答