1

我试图从我的方法中获取值并将其显示在另一个类中作为祝酒词（只是为了确保我的方法有效）。我得到一个我似乎无法弄清楚的空指针异常，我尝试了多种不同的东西。我什至尝试给我的字符串值“This”和“That”。然后我的日志猫告诉我

04-05 21:17:29.633：E/AndroidRuntime(18838)：java.lang.RuntimeException：无法启动活动 ComponentInfo{com.cerealBarApps/com.cerealBarApps.Testing}：android.content.res.Resources$NotFoundException：字符串资源 ID #0x0

这是我想用来运行一切的类。

public class Testing extends Activity {

    /** Called when the activity is first created. */
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);
        String Testeroni = "This";
        String Testerhynocerous = "That";

        LoginTest test = new LoginTest();

        Toast.makeText(getApplicationContext(), (test.TestUsername(Testeroni)),
                Toast.LENGTH_SHORT).show();

        Toast.makeText(getApplicationContext(),
                (test.TestPassword(Testerhynocerous)), Toast.LENGTH_SHORT)
                .show();

    }
}

这是我要从中运行方法的类。

public class LoginTest {

    // 0 = Username length is less than 4 or greater than 15
    // 1 = Username character is not a letter/or digit
    // 9 = Everything is okay in username :)
    public int TestUsername(String username) {
        if (username.length() <= 4 || username.length() >= 15) {

            return 0;
        }

        for (int i = 0; i < username.length(); i++) {
            if (Character.isDigit(username.charAt(i))
                    || Character.isJavaLetter(username.charAt(i))) {
                System.out.println("");
                // Do Nothing
            } else

                return 1;
        }
        return 9;
    }



        // 2 = Passowrd length is less than 4 or greater than 15
        // 3 = Password character is not a digit
        // 8 = Everything is okay in password :)
        public int TestPassword(String password) {
            if (password.length() <= 4 || password.length() >= 15) {
                return 2;
            }

            for (int i = 0; i < password.length(); i++) {
                if (Character.isDigit(password.charAt(i))
                        || Character.isJavaLetter(password.charAt(i))) {
                    System.out.println("");
                    // Do Nothing
                } else
                    return 3;
            }
            return 8;
        }
    }
4

2 回答 2

1

问题在这里：

Toast.makeText(getApplicationContext(), (test.TestUsername(Testeroni)),
            Toast.LENGTH_SHORT).show();

TestUsername 返回一个 int，它被解释为资源 id，这当然是无效的。

将其更改为：

Toast.makeText(getApplicationContext(), String.valueOf((test.TestUsername(Testeroni))),
            Toast.LENGTH_SHORT).show();
于 2012-04-06T01:27:19.767 回答
1

这些代码：

Toast.makeText(getApplicationContext(), (test.TestUsername(Testeroni)),
            Toast.LENGTH_SHORT).show();

    Toast.makeText(getApplicationContext(),
            (test.TestPassword(Testerhynocerous)), Toast.LENGTH_SHORT)
            .show();

有问题，test.TestUsername(Testeroni)返回test.TestPassword(Testerhynocerous)类型是int，所以想成字符串res id，所以if可以改成这样：

 Toast.makeText(getApplicationContext(), (""+test.TestUsername(Testeroni)),
            Toast.LENGTH_SHORT).show();

    Toast.makeText(getApplicationContext(),
            (""+test.TestPassword(Testerhynocerous)), Toast.LENGTH_SHORT)
            .show();
于 2012-04-06T01:28:12.920 回答