sql - 计算 SQL 字符串值中字符的出现次数？

Question

如果您有电子邮件地址

you.late.you@asdf.com

you_late_you@asdf.com

如果使用 sql 代码有 2 个点/下划线，如何启用计数？

Answer 1

select len('you.late.you@asdf.com') - len(replace('you.late.you@asdf.com', '.', ''))

Answer 2

这会给你想要的结果。

 DECLARE @str VARCHAR(1000)
SET @str = 'you.l_ate.you@as_df.com'
SELECT (LEN(@str)- LEN(REPLACE(@str ,'.' ,'')))+(LEN(@str)- LEN(REPLACE(@str ,'_' ,'')))

答案：5

Answer 3

我想他想数@之前没有点的字母：

declare @myEmail varchar(50)
set @myEmail = 'you.late.you@asdf.com'

declare @mySearch varchar(50)
set @mySearch = SUBSTRING (@myEmail,0 , PATINDEX( '%@%',@myEmail))
select (LEN(REPLACE(@mySearch, '.', '')))

Answer 4

如果要计算具有两个.or的行数_，可以执行以下操作：

select count(*) 
  from mytable 
 where left(email, charindex('@', email)) like '%[._]%[._]%'

leftandcharindex用于忽略域名（将有）.。

参考：LIKE（TSQL，SQL Server 2008）

Answer 5

select 
    length(substr('you.late.you@asdf.com',1,INSTR('you.late.you@asdf.com','@',1))) - 
    length(replace(substr('you.late.you@asdf.com',1,INSTR('you.late.you@asdf.com','@',1)), '.', '')) 
from dual