-5

生成此文件所需的 ToString 格式是什么

>     5  to 00000500
>     10 to 00001000
>     15 to 00001500
>     20 to 00002000

谢谢。

4

4 回答 4

4

如果您只想使用ToString格式字符串执行此操作,而不是也涉及乘法,那么您可以使用以下内容:

string yourString = yourNumber.ToString("000000'00'");
于 2012-04-05T10:56:47.540 回答
3

尝试做

(yourNum * 100).ToString("0000000");
于 2012-04-05T10:52:16.000 回答
2
(number * 100).ToString("D8");
于 2012-04-05T10:55:20.900 回答
1

您可以使用自定义格式提供程序来做到这一点。前提是输入是一个字符串。不过,它很容易更改为任何数据类型。只需将其更改if (arg.GetType() == typeof(String))为您想要格式化的任何内容。

用法:

            var five = "5";
            var ten = "10";
            var fiveteen = "15";
            var twenty = "20";

        var formatprovider = new CustomStringFormatProvider();
        var res1 = string.Format(formatprovider, "{0}", five);
        res1 = string.Format(formatprovider, "{0}", ten);
        res1 = string.Format(formatprovider, "{0}", fiveteen);
        res1 = string.Format(formatprovider, "{0}", twenty);

这是格式提供程序

public sealed class CustomStringFormatProvider : IFormatProvider, ICustomFormatter
{
    public Object GetFormat(Type formatType)
    {
        if (formatType == typeof(ICustomFormatter)) return this;
        return Thread.CurrentThread.CurrentCulture.GetFormat(formatType);
    }
    public String Format(String format, Object arg, IFormatProvider formatProvider)
    {
        String s;

        IFormattable formattable = arg as IFormattable;

        if (formattable == null) s = arg.ToString();
        else s = formattable.ToString(format, formatProvider);

        if (arg.GetType() == typeof(String))
            return String.Join("",Enumerable.Repeat("0", 4).ToArray()) + s + String.Join("",Enumerable.Repeat("0", 4 - s.Length).ToArray());
        return s;
    }
}
于 2012-04-05T11:20:23.393 回答