当我试图从数据库中回显列计数器的值时,我收到了 Resource id #3 错误。我只想获得一个值。有什么想法我该怎么做?
$Page = $_SERVER['PHP_SELF'];
$num = preg_replace("/[^0-9]/", '', $Page);
$query = "SELECT * FROM hitscounter WHERE page='$num';";
$res = mysql_query($query);
if (mysql_num_rows($res) > 0) {
mysql_query("UPDATE hitscounter SET counter=counter+1 Where page='$num'");
$views = mysql_query("SELECT counter FROM hitscounter WHERE page=555");
mysql_fetch_array($views, MYSQL_NUM);
mysql_free_result($views);
echo $views;
}