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我将以下 json 数据作为海报正文的参数发送

zip='{"zipcode":"501234","cityname":"hyd","countyname" : "Poweshiek","statename" : "Iowa"}'&Accept=application%2Fjson

我收到错误

'

MultiJson::DecodeError`在此处输入代码` 

743: 'zip='{"zipcode":"501234","cityname":"hyd","countyname" : "Poweshiek","statename" : "Iowa"}'&Accept=application%2Fjson' 处出现意外标记

Rails.root: e:/rails/vivadesi

' 下面是日志文件： '在 2012-04-05 07:31:17 +0530 解析请求参数时发生错误，为 127.0.0.1 开始 PUT "/orgs/updatezip.json?id=4f676eb33e454911a000aea1"。内容：

MultiJson::DecodeError (743: 'zip='{"zipcode":"501234","cityname":"hyd","countyname" : "Poweshiek","statename" : "Iowa"}'&Accept=应用程序%2Fjson'):

渲染 gem/ruby/1.9.1/gems/actionpack-3.1.0/lib/action_dispatch/middleware/templates/rescues/_trace.erb (1.0ms) 渲染 gem/ruby/1.9.1/gems/actionpack-3.1.0 /lib/action_dispatch/middleware/templates/rescues/_request_and_response.erb (1.0ms) 在救援中渲染 gem/ruby/1.9.1/gems/actionpack-3.1.0/lib/action_dispatch/middleware/templates/rescues/diagnostics.erb /布局（12.0毫秒）'

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1 回答 1

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您通过邮寄或获取发送，因为当您尝试将字符串转换为 json（格式参数）时会出现此错误。

'zip' 将是一个想要获取代码的变量。
& Accept = application% 2Fjson 可以作为 json 中的参数

示例
发送 json 用于测试 

zip='{"zipcode":"501234","cityname":"hyd","countyname" : "Poweshiek","statename" : "Iowa"}'&Accept=application%2Fjson

{"zip":{"zipcode":"501234","cityname":"hyd","countyname" : "Poweshiek","statename" : "Iowa"},"accept":"application%2Fjson"}
于 2013-01-26T02:46:36.870 回答