可能重复：
带 x86-64 组件的谐波系列
试图在汇编中做一个谐波系列的版本
当前代码采用 1 + 1/2 + 1/3 + 1/4 + 1/n 直到求和的值大于输入的值。（浮点值）
当前代码在第一次循环后退出循环并打印出 .33333
这是我的退出条件吗？
denominator:
xor r14,r14 ;zero out r14 register
add r14, 2 ;start counter at 2
fld1 ;load 1 into st0
fxch st2
denomLoop:
fld1
mov [divisor], r14 ;put 1 into st0
fidiv dword [divisor] ;divide st0 by r14
inc r14 ;increment r14
fst qword [currentSum] ;pop current sum value into currentSum
addParts:
fxch st2 ;put the current value that is in st2 into st0
fadd qword [currentSum] ;add result of first division to 1
fxch st2 ;place result of addition into st2
fld qword [realNumber] ;place real number into st0
;compare to see if greater than inputed value
fcom st2 ;compare st0 with st2
fstsw ax ;needed to do floating point comparisons on FPU
sahf ;needed to do floating point comaprisons on FPU
jae done ;jump if greater than
jmp denomLoop ;jump if less than