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我收到了这个错误,但它并没有帮助我靠近错误发生的位置。错误后面的数字是什么意思?过去几个小时我一直在查看错误,但我并没有真正了解错误的来源。我的代码是:

val str = "(and x y)";

def stringParse ( exp: String, expreshHolder: ArrayBuffer[String] ): ArrayBuffer[String] = { //takes three arguments, string, int, arraybuffer

    var b = 0; //position of where in the expression String I am currently in
    var temp = expreshHolder; //holder of expressions without parens
    if(temp == 0) b = 0; else {b = temp(temp.length-1).toInt; temp.remove(temp.length-1)} //this sets the position of wherever the string was read last plus removes that check from the end of the ArrayBuffer
    var arrayCounter = temp.length; //just counts to make sure an empty spot in the array is there to put in the strings

    if(exp(b) == '(') {
        b = b + 1;

        while(exp(b) == ' '){b = b + 1;} //point of this is to just skip any spaces between paren and start of expression type
        if(exp(b) == 'a') {
            //first create the 'and', 'or', 'not' expression types to figure out 
            temp += exp(b).toString; 
            b = b+1; 
            temp(arrayCounter) = temp(arrayCounter) + exp(b).toString; //concatenates the second letter
            b = b+1; 
            temp(arrayCounter) = temp(arrayCounter) + exp(b).toString; //concatenates the last letter for the expression type
            arrayCounter+=1
            //this part now takes the symbols and puts them in an array
            b+=1;
            while(exp(b) == ' ') {b+=1;} //just skips any spaces until it reaches the first symbol
            if(exp(b) == '(') { temp += b.toString; temp = stringParse(exp, temp);
            b = temp(temp.length-1).toInt; 
            temp.remove(temp.length-1); 
            arrayCounter = temp.length 
            } else {
            temp += exp(b).toString; 
            arrayCounter+=1; b+=1; }
            while(exp(b) == ' ') {b+=1;} //just skips any spaces until it reaches the second symbol

            if(exp(b) == '(') { temp += b.toString; temp = stringParse(exp, temp); 
                            b = temp(temp.length-1).toInt; 
                            temp.remove(temp.length-1); 
                            arrayCounter = temp.length } else {temp += exp(b).toString; arrayCounter+=1; b+=1; }    
        }
    temp;
    } else { 
      temp(arrayCounter) +="failed"; temp;} //this is just incase it fails and I should probably check this incase it fails when it doesnt encounter an opening paren
}//end of while loop

hold = stringParse(str, ho );
for(test <- hold) println(test);

很抱歉代码量很大,但据我所知,它是正确的。这段代码的重点是读取顶部的第一个字符串,然后将“and”、“x”、“y”放入数组中。它应该在更复杂的版本上进行,但我首先在一个简单的版本上尝试它以测试并确保它有效。我得到的错误是:

java.lang.ArrayIndexOutOfBoundsException: -1
at scala.collection.mutable.ResizableArray$class.apply(ResizableArray.scala:45)
at scala.collection.mutable.ArrayBuffer.apply(ArrayBuffer.scala:44)
at Driver$.stringParse$1(Driver.scala:19)
at Driver$.main(Driver.scala:60)
at Driver.main(Driver.scala)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25)
at java.lang.reflect.Method.invoke(Method.java:597)
at scala.tools.nsc.util.ScalaClassLoader$$anonfun$run$1.apply(ScalaClassLoader.scala:78)
at scala.tools.nsc.util.ScalaClassLoader$class.asContext(ScalaClassLoader.scala:24)
at scala.tools.nsc.util.ScalaClassLoader$URLClassLoader.asContext(ScalaClassLoader.scala:88)
at scala.tools.nsc.util.ScalaClassLoader$class.run(ScalaClassLoader.scala:78)
at scala.tools.nsc.util.ScalaClassLoader$URLClassLoader.run(ScalaClassLoader.scala:101)
at scala.tools.nsc.ObjectRunner$.run(ObjectRunner.scala:33)
at scala.tools.nsc.ObjectRunner$.runAndCatch(ObjectRunner.scala:40)
at scala.tools.nsc.MainGenericRunner.runTarget$1(MainGenericRunner.scala:56)
at scala.tools.nsc.MainGenericRunner.process(MainGenericRunner.scala:80)
at scala.tools.nsc.MainGenericRunner$.main(MainGenericRunner.scala:89)
at scala.tools.nsc.MainGenericRunner.main(MainGenericRunner.scala)

对能够阅读此错误消息并了解它发生的位置有任何帮助吗?提前致谢。

4

2 回答 2

6

错误在第 19 行Driver.scala

at Driver$.stringParse$1(Driver.scala:19)

看一眼:

if(temp == 0) b = 0; else {b = temp(temp.length-1).toInt; temp.remove(temp.length-1)} 

temp是一个ArrayBuffer[String],而不是一个数字,所以temp == 0总是假的。这意味着该else子句将始终执行,即使temp.length是 0。

于 2012-04-05T01:09:22.753 回答
6

这意味着您要递减的变量已达到-1

另请注意,您需要做的就是按照行号。例如,首先要查看的位置是第 '45' 行

 scala.collection.mutable.ResizableArray$class.apply(ResizableArray.scala:45)

处理您首先编写的方法。

于 2012-04-04T23:53:36.700 回答