4

我无法返回 JSONArray，而是我的对象似乎是一个字符串。myArray的值与jsonString的值相同。该对象是 String 对象而不是JSONArray。以及jsonString和myArray prnt：

[{"id":"100002930603211",
  "name":"Aardvark Jingleheimer",
  "picture":"shortenedExample.jpg" },
 {"id":"537815695",
   "name":"Aarn Mc",
   "picture":"shortendExample.jpg" },
 {"id":"658471072",
   "name":"Adrna opescu",
   "picture":"shortenedExample.jpg"
}]

如何将其转换为实际的 Java JSONArray？谢谢！

           //arrPersons is an ArrayList

        Gson gson = new Gson();
        String jsonString = gson.toJson(arrPersons);

        JsonParser parser = new JsonParser();
        JsonElement myElement = parser.parse(jsonString);
        JsonArray myArray = myElement.getAsJsonArray();
4

2 回答 2

1

我认为你可以做你想做的事，而无需写出一个 json 字符串然后重新读取它：

List<Person> arrPersons = new ArrayList<Person>();

// populate your list

Gson gson = new Gson();
JsonElement element = gson.toJsonTree(arrPersons, new TypeToken<List<Person>>() {}.getType());

if (! element.isJsonArray()) {
// fail appropriately
    throw new SomeException();
}

JsonArray jsonArray = element.getAsJsonArray();
于 2012-08-02T14:52:55.760 回答
0 
    public JSONArray getMessage(String response){

    ArrayList<Person> arrPersons = new ArrayList<Person>();
    try {
        // obtain the response
        JSONObject jsonResponse = new JSONObject(response);
        // get the array
        JSONArray persons=jsonResponse.optJSONArray("data");


        // iterate over the array and retrieve single person instances
        for(int i=0;i<persons.length();i++){
            // get person object
            JSONObject person=persons.getJSONObject(i);
            // get picture url
            String picture=person.optString("picture");
            // get id
            String id=person.optString("id");
            // get name
            String name=person.optString("name");

            // construct the object and add it to the arraylist
            Person p=new Person();
            p.picture=picture;
            p.id=id;
            p.name=name;
            arrPersons.add(p);
        }
        //sort Arraylist
        Collections.sort(arrPersons, new PersonSortByName());


    Gson gson = new Gson();
    //gson.toJson(arrPersons);

    String jsonString = gson.toJson(arrPersons);

    sortedjsonArray = new JSONArray(jsonString);



    } catch (JSONException e) {

        e.printStackTrace();
    }

    return sortedjsonArray;

}



public class PersonSortByName implements Comparator<Person>{

    public int compare(Person o1, Person o2) {
    return o1.name.compareTo(o2.name);
    }
    }

  public class Person{
       public String picture;
       public String id;
       public String name;
  }
于 2012-04-05T17:53:03.063 回答