0

我正在通过数据库构建类别管理器。下面的 PHP 生成了我将在下面粘贴的代码:

function generate_menu($parent, $menu_array, $result = NULL)
{
    $has_childs = FALSE;

    foreach($menu_array as $key => $value):
        if ($value['parent'] == $parent):
            $result .= '<li id="list_'.$value['id'].'" class="item">';
            $result .= '<div class="item">' . $value['name'] . '</div>';

            if ($has_childs):
                $has_childs = FALSE;
                $result .= '<ol>';
            else:
                $has_childs = TRUE;
                $result .= '</li>';
            endif; 

            $result .= $this->generate_menu($key, $menu_array);
        endif;
    endforeach;

    return $result;
}

这是它生成的 HTML:

<li id="list_11" class="item">
    <div class="item">Real Estate</div>
</li>
<li id="list_12" class="item">
    <div class="item">Home Improvements</div>
    <ol>
        <li id="list_13" class="item">
            <div class="item">Interior</div>
        </li>
        <li id="list_14" class="item">
            <div class="item">Exterior</div>
            <ol>
                <li id="list_15" class="item">
                    <div class="item">Exterior Subcat</div>
                </li>

因此,当它是父项时,我可以关闭<li>标签,但如果它是具有父项的项目,则 an<ol>进入等式。那时我不知道如何关闭它们。我不确定在哪里放置</li>and </ol>。我尝试过的一切都行不通。

这是它的外观

<li id="list_11" class="item">
    <div class="item">Real Estate</div>
</li>
<li id="list_12" class="item">
    <div class="item">Home Improvements</div>
    <ol>
        <li id="list_13" class="item">
            <div class="item">Interior</div>
        </li>
        <li id="list_14" class="item">
            <div class="item">Exterior</div>
            <ol>
                <li id="list_15" class="item">
                    <div class="item">Exterior Subcat</div>
                </li>
            </ol>
        </li>
    </ol>
</li>

编辑:

这是传递数组和生成菜单的代码:

$query = $this->db->get('categories');

foreach($query->result_array() as $row):
    $menu_array[$row['id']] = array('name' => $row['name'], 'parent' => $row['parent'], 'id' => $row['id']);
endforeach;

echo '<ol class="sortable">';
echo $this->tasks->generate_menu(0, $menu_array);
echo '</ol>';

这是 $menu_array 的 print_r:

Array
(
    [11] => Array
        (
            [name] => Real Estate
            [parent] => 
            [id] => 11
        )

    [12] => Array
        (
            [name] => Home Improvements
            [parent] => 
            [id] => 12
        )

    [13] => Array
        (
            [name] => Interior
            [parent] => 12
            [id] => 13
        )

    [14] => Array
        (
            [name] => Exterior
            [parent] => 12
            [id] => 14
        )

    [15] => Array
        (
            [name] => Exterior Subcat
            [parent] => 
            [id] => 15
        )

)
4

2 回答 2

0

我已经弄清楚了这一点。我把事情复杂化了一点。

function generate_menu($parent, $menu_array, $result = NULL)
{       
    foreach($menu_array as $key => $value):
        if ($value['parent'] == $parent):
            $result .= '<li id="list_'.$value['id'].'" class="item">';
            $result .= '<div class="item">' . $value['name'] . '</div>';
            $result .= '<ol>';
            $result .= $this->generate_menu($key, $menu_array);
            $result .= '</li></ol>';
        endif;
    endforeach;

    return $result;
}
于 2012-04-04T22:49:22.997 回答
0

为了正确使用递归函数,值数组需要像这样反映层次结构:

array(
[11] => "Real Estate",
[12] => array(
    [0] => "Home Improvements",
    [13] => "Interior",
    [14] => "Exterior"
    ),
[15] => "Exterior Subcat"
)

该函数现在可以遍历 11,正常添加一个列表项。在 12 时,它会遇到一个数组而不是字符串(使用gettype($value)),因此它不会添加一个列表项,而是会再次调用自身 - 将它刚刚找到的数组作为参数传递。这在理论上允许无限数量的级别。

function make_menu($menu_array) {

    $result = "<ol>";

    foreach($menu_array as $k=>$v)
    {
        $result .= '<li id="list_'.$k.'" class="item">';

        if(gettype($v) == 'array')
        {
            $result .= '<div class="item">' . $v[0] . '</div>';
            unset($v[0]);
            $result .= make_menu($v);
        }
        elseif(gettype($v) == 'string')
        {
            $result .= '<div class="item">' . $v . '</div>';
        }

        $result .= '</li>';
    }
    $result .= "</ol>";
    return $result;
}
于 2012-04-04T23:10:24.680 回答