36

是否有简单的方法可以在 Java 中实现进程的滚动百分比,以显示在控制台中?我有一个在特定过程中生成的百分比数据类型(双精度),但我可以将它强制到控制台窗口并刷新它,而不是为每个新的百分比更新打印一个新行吗?我正在考虑推送 cls 和更新,因为我在 Windows 环境中工作,但我希望 Java 具有某种内置功能。欢迎所有建议!谢谢!

4

9 回答 9

55

您可以打印回车\r将光标放回行首。

例子:

public class ProgressDemo {
  static void updateProgress(double progressPercentage) {
    final int width = 50; // progress bar width in chars

    System.out.print("\r[");
    int i = 0;
    for (; i <= (int)(progressPercentage*width); i++) {
      System.out.print(".");
    }
    for (; i < width; i++) {
      System.out.print(" ");
    }
    System.out.print("]");
  }

  public static void main(String[] args) {
    try {
      for (double progressPercentage = 0.0; progressPercentage < 1.0; progressPercentage += 0.01) {
        updateProgress(progressPercentage);
        Thread.sleep(20);
      }
    } catch (InterruptedException e) {}
  }
}
于 2009-06-16T13:03:30.513 回答
14

我使用以下代码:

public static void main(String[] args) {
    long total = 235;
    long startTime = System.currentTimeMillis();

    for (int i = 1; i <= total; i = i + 3) {
        try {
            Thread.sleep(50);
            printProgress(startTime, total, i);
        } catch (InterruptedException e) {
        }
    }
}


private static void printProgress(long startTime, long total, long current) {
    long eta = current == 0 ? 0 : 
        (total - current) * (System.currentTimeMillis() - startTime) / current;

    String etaHms = current == 0 ? "N/A" : 
            String.format("%02d:%02d:%02d", TimeUnit.MILLISECONDS.toHours(eta),
                    TimeUnit.MILLISECONDS.toMinutes(eta) % TimeUnit.HOURS.toMinutes(1),
                    TimeUnit.MILLISECONDS.toSeconds(eta) % TimeUnit.MINUTES.toSeconds(1));

    StringBuilder string = new StringBuilder(140);   
    int percent = (int) (current * 100 / total);
    string
        .append('\r')
        .append(String.join("", Collections.nCopies(percent == 0 ? 2 : 2 - (int) (Math.log10(percent)), " ")))
        .append(String.format(" %d%% [", percent))
        .append(String.join("", Collections.nCopies(percent, "=")))
        .append('>')
        .append(String.join("", Collections.nCopies(100 - percent, " ")))
        .append(']')
        .append(String.join("", Collections.nCopies(current == 0 ? (int) (Math.log10(total)) : (int) (Math.log10(total)) - (int) (Math.log10(current)), " ")))
        .append(String.format(" %d/%d, ETA: %s", current, total, etaHms));

    System.out.print(string);
}

结果: 在此处输入图像描述

于 2016-08-31T19:51:44.760 回答
9

我已经用 Java 编写了这样的包。

https://github.com/ctongfei/progressbar

于 2015-06-18T14:02:39.990 回答
6

我认为没有内置功能可以满足您的需求。

有一个库可以做到这一点(JLine)。

看这个教程

于 2009-06-16T12:56:41.807 回答
4

我很确定没有办法更改控制台已经打印的任何内容,因为 Java 认为控制台(标准输出)是一个 PrintStream。

于 2009-06-16T12:58:26.717 回答
2

不知道 java 本身内置的任何内容,但您可以使用终端控制代码来执行重新定位光标等操作。这里有一些细节:http ://www.termsys.demon.co.uk/vtansi.htm

于 2009-06-16T12:58:35.983 回答
0

通过运行特定于操作系统的命令清除控制台,然后打印新的百分比

于 2009-06-16T13:02:23.590 回答
0
import java.util.Random;

public class ConsoleProgress {

    private static String CURSOR_STRING = "0%.......10%.......20%.......30%.......40%.......50%.......60%.......70%.......80%.......90%.....100%";

    private static final double MAX_STEP = CURSOR_STRING.length() - 1;

    private double max;
    private double step;
    private double cursor;
    private double lastCursor;

    public static void main(String[] args) throws InterruptedException {
        // ---------------------------------------------------------------------------------
        int max = new Random().nextInt(400) + 1;
        // ---------------------------------------------------------------------------------
        // Example of use :
        // ---------------------------------------------------------------------------------
        ConsoleProgress progress = new ConsoleProgress("Progress (" + max + ") : ", max);
        for (int i = 1; i <= max; i++, progress.nextProgress()) {
            Thread.sleep(3L); // a task with no prints
        }
    }

    public ConsoleProgress(String title, int maxCounts) {
        cursor = 0.;
        max = maxCounts;
        step = MAX_STEP / max;
        System.out.print(title);
        printCursor();
        nextProgress();
    }

    public void nextProgress() {
        printCursor();
        cursor += step;
    }

    private void printCursor() {
        int intCursor = (int) Math.round(cursor) + 1;
        System.out.print(CURSOR_STRING.substring((int) lastCursor, intCursor));
        if (lastCursor != intCursor && intCursor == CURSOR_STRING.length())
            System.out.println(); // final print
        lastCursor = intCursor;
    }
}
于 2017-03-18T20:52:31.890 回答
0

派对迟到了,但这里有一个答案:

public static String getSingleLineProgress(double progress) {
    String progressOutput = "Progress: |";
    String padding = Strings.padEnd("", (int) Math.ceil(progress / 5), '=');
    progressOutput += Strings.padEnd(padding, 0, ' ') + df.format(progress) + "%|\r";
    if (progress == 100.0D) {
        progressOutput += "\n";
    }
    return progressOutput;
}

记得使用System.out.print()而不是System.out.println()

于 2017-05-18T19:52:27.993 回答