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我想要一个以一种格式(Postgis 地理格式)存储数据的列,但是每当它受到选择查询时,它应该用函数转换并以另一种格式返回。

可能吗?

它会影响像这样的查询吗

Update table set other_column = do_comething(column_with_transform_rule)
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1 回答 1

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CREATE VIEW clueless AS (
    SELECT na.a, na.b,na.c
       , se.d,se.e, se.f
       , do_something_usefull ( na.g, se.i, 'clue' ) AS usefull
    FROM nameless na
    JOIN sense se ON se.clue_id = na.clue_id
    -- .. maybe more 
    );

更新:在得到正确的要求之后,这件事可以使用规则来完成。

SET search_path='tmp';

-- Create a table and a view on it
DROP TABLE nameless CASCADE;
CREATE TABLE nameless
        ( a INTEGER NOT NULL
        , b INTEGER NOT NULL
        , PRIMARY KEY (a,b)
        );
CREATE VIEW clueless AS (
        SELECT a, b
        , a*b AS c
         FROM nameless
        );
-- Enter some data
INSERT INTO nameless(a,b)
        SELECT a, b 
        FROM generate_series(1,5) a
        , generate_series(11,12) b
        ;

CREATE RULE clue_i AS
        ON INSERT TO clueless
        DO INSTEAD (
        INSERT INTO nameless(a,b)
        VALUES (NEW.a, NEW.b)
                ;
        );

CREATE RULE clue_d AS
        ON DELETE TO clueless
        DO INSTEAD (
        DELETE FROM nameless na
        WHERE na.a = OLD.a AND na.b = OLD.b
                ;
        );

CREATE RULE clue_u AS
        ON UPDATE TO clueless
        DO INSTEAD (
        UPDATE nameless na
        SET a = NEW.a, b = NEW.b
        WHERE na.a = OLD.a AND na.b = OLD.b
                ;
        );

SELECT * FROM clueless;

INSERT INTO clueless(a,b)
SELECT 5+src.a, src.b-10
FROM clueless src
WHERE src.a >=4
        ;

-- EXPLAIN ANALYZE
UPDATE clueless
SET b=b+20
WHERE b < 10
        ;

SELECT * FROM clueless;

结果:

NOTICE:  drop cascades to view clueless
DROP TABLE
NOTICE:  CREATE TABLE / PRIMARY KEY will create implicit index "nameless_pkey" for table "nameless"
CREATE TABLE
CREATE VIEW
INSERT 0 10
CREATE RULE
CREATE RULE
CREATE RULE
 a | b  | c  
---+----+----
 1 | 11 | 11
 1 | 12 | 12
 2 | 11 | 22
 2 | 12 | 24
 3 | 11 | 33
 3 | 12 | 36
 4 | 11 | 44
 4 | 12 | 48
 5 | 11 | 55
 5 | 12 | 60
(10 rows)

INSERT 0 4
UPDATE 4
 a  | b  |  c  
----+----+-----
  1 | 11 |  11
  1 | 12 |  12
  2 | 11 |  22
  2 | 12 |  24
  3 | 11 |  33
  3 | 12 |  36
  4 | 11 |  44
  4 | 12 |  48
  5 | 11 |  55
  5 | 12 |  60
  9 | 21 | 189
  9 | 22 | 198
 10 | 21 | 210
 10 | 22 | 220
(14 rows)

额外说明:规则被视为完成此类事情的首选方式。

于 2012-04-04T09:21:01.477 回答