TL;博士
如何减少重复代码以下,例如创建两个作业/触发器job-inventory
,而不是重复两次并创建术语
;; deps in project.clj
;; [clojurewerkz/quartzite "2.1.0"]
(ns hello.scheduler
(:require [clojurewerkz.quartzite.scheduler :as qs]
[clojurewerkz.quartzite.triggers :as t]
[clojurewerkz.quartzite.jobs :as j]
[clojurewerkz.quartzite.jobs :refer [defjob]]
[clojurewerkz.quartzite.schedule.cron :as cron])
(:use clojure.tools.logging)
(:gen-class))
(def job-inventory
[{:name "add" :task '(+ 1 1) :cron "0/5 * * ? * *"}
{:name "multiply" :task '(* 4 5) :cron "0/3 * * ? * *"}])
(defjob add [ctx] (info "add called, return" (+ 1 1)))
(defjob multiply [ctx] (info "multiply called, return" (* 2 3)))
(defn auto
[]
(let [s (-> (qs/initialize) qs/start)
_ (qs/clear! s)
job (j/build
(j/of-type add)
(j/with-identity (j/key "job.add")))
trigger (t/build
(t/with-identity (t/key "trigger.add"))
(t/start-now)
(t/with-schedule (cron/schedule
(cron/cron-schedule "0/5 * * ? * *"))))
_ (qs/schedule s job trigger)
job (j/build
(j/of-type multiply)
(j/with-identity (j/key "job.multiply")))
trigger (t/build
(t/with-identity (t/key "trigger.multiply"))
(t/start-now)
(t/with-schedule (cron/schedule
(cron/cron-schedule "0/3 * * ? * *"))))
_ (qs/schedule s job trigger)
]
))
类似于http://clojurequartz.info/articles/getting_started.html中描述的内容,我有代码块来创建作业并将它们挂钩以执行
问题是,当我得到越来越多的它们时,我想知道我是否可以有更好的方法来管理它们,比如 create / spawn from that job-inventory
,而不是实际创建像add
or这样的变量multiply
所以,要求多一层循环 有没有办法利用函数编程,并避免创建新名称(用传统语言说 python qt,如果我有一组按钮,我可以砸进一个巨大的字典,然后循环创建/禁用,而不是实际将每个名称创建为顶级变量)
我试过宏,但它说无法解析类添加,所以猜我用错了