9

We're using kernel version 2.4-20 and we need to count number of active users, in kernel mode. Objective is to change the scheduler, so we are in sched.c, modifying schedule() function.

What we do is to count the users in list_for_each macro. 

list_for_each(tmp, &runqueue_head) {
    p = list_entry(tmp, struct task_struct, run_list);
    if (can_schedule(p, this_cpu)) {
        if (unique(p->uid)) add_new_user(p->uid);
        int weight = goodness(p, this_cpu, prev->active_mm);
        if (weight > c)
            c = weight, next = p;
    }
}

which is basically adding unique users to a list. However, we get random results. Is there a concrete way to solve this problem?

Thank you.

4

2 回答 2

1

You may want to try counting the users inside the for_each_task macro. This results in counting the users that have a task which is blocked due to I/O or any other reason. This should provide better results as you can't guarantee being able to count the users who run interactive processes if you use the run queue.

于 2012-06-02T18:33:57.207 回答
0

Would this work? who | awk ' { print $1 }' | sort -ud

于 2012-06-04T19:18:44.180 回答