10

我对休眠和标准有疑问。我有两个课程:

public class Place{
    long id;
    String name;
    Set<Street> streets;
}

public class Street{
    long id;
    String name;
    Place place;
}

我现在想编写一个方法,它返回一个名称与参数中给出的名称相似的地点列表和一个名称与参数中给出的相似的街道。

public List<Place> findPlaces(String name, String streetname){
    //getSession() gives me a hibernate session
    Criteria crit = getSession().createCriteria(Place.class, "place");
    crit.add(Restrictions.like("name", name+"%"));
    //Everything works fine until here
    //Last step: Sort out all places not containing a street named like streetname + "%"
}

最后一步我尝试了不同的方法:

//streetList is a list of all streets named like streetname
crit.add(Restrictions.in("streets", streetList));

其他方式:

DetachedCriteria strasseCrit = DetachedCriteria.forClass(Street.class, "street");
streetCrit.add(Restrictions.like("street.name", streetname + "%"));
streetCrit.createAlias("street.place", "streetPlace");
streetCrit.add(Restrictions.eqProperty("streetPlace.id", "place.id"));
streetCrit.setProjection(Projections.property("street.name"));
crit.add(Subqueries.exists(streetCrit));

最后一种方式:

crit.createAlias("place.streets", "street");
crit.add(Restrictions.like("street.name", streetname + "%"));
crit.setResultTransformer(DistinctResultTransformer.INSTANCE);

我希望你能理解我的问题并对我的英语不好表示抱歉:(

我搜索了两天的解决方案,我不知道如何继续......

来自德国的问候 :) Philipp

4

1 回答 1

13
public List<Place> findPlaces(String name, String streetname){
    Criteria crit = getSession().createCriteria(Place.class, "place");
    criteria.createAlias("streets", "s");  // Create alias for streets
    crit.add(Restrictions.like("s.name", name+"%"));
    // continue method
}
于 2012-04-02T20:11:08.173 回答