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我有两个要比较的字符串变量。

var compareA = "something.somethingelse.another.something2"
var compareB = "*.another.something2"

我想比较一下,结果是:True

var compareC = "something.somethingelse.*"

与 compareA 相比,结果也应该是:True

当然,两个变量都可以包含 N 个点这一事实也使任务复杂化。你会如何开始为他?

我试过这个:

 static void Main(string[] args)
    {

        var A = CompareString("*.something", "other.Another.something"); //I need this is true!
        var B = CompareString("something.Value.Other.*", "something.Value.Other.SomethingElse"); //I need this is true
        var C = CompareString("something.Value.Other", "something.Value.Other.OtherElse"); //I need this is False
        var D = CompareString("*.somethingElse", "other.another.Value"); //I Need this is false

        Console.WriteLine("It is need True: {0}", A);
        Console.WriteLine("It is need True: {0}", B);
        Console.WriteLine("It is need False: {0}", C);
        Console.WriteLine("It is need False: {0}", D);
}



        private static bool CompareString(string first, string second) 
    {
        var resume = false;
        var firstSplit = first.Split('.');
        var secondSplit = second.Split('.');
        foreach (var firstItem in firstSplit)
        {
            foreach (var secondItem in secondSplit)
            {
                if (firstItem == "*" || secondItem == "*" || string.Equals(firstItem.ToLower(), secondItem.ToLower()))
                {
                    resume = true;
                }
                else
                {
                    resume = false;
                }
            }
        }
        return resume;
    }

结果是好的,但我认为可以做不同的事情,推理可能是错误的。

4

1 回答 1

0

假设如下:

  • 将 1 个字符串与另一个字符串进行比较,它是 1 的完整字符串,包含在 2 个字符串中较长的字符串中。
  • 被忽视的案例以及文化。
  • 句号被认为是字符串的一部分,实际上并不是分隔符。
  • 通配符可用于说明一个字符串如何包含在另一个字符串中。

您应该能够使用以下内容

    private bool HasMatch(string textToSearch, string searchText)
    {
        if (textToSearch.Length < searchText.Length) return false;

        var wildCardIndex = searchText.IndexOf('*');

        if (wildCardIndex == -1)
        {
            return textToSearch.Equals(searchText, StringComparison.InvariantCultureIgnoreCase);
        }
        else
        {
            if (wildCardIndex == 0)
            {
                var text = searchText.TrimStart('*');
                return textToSearch.EndsWith(text, StringComparison.InvariantCultureIgnoreCase);
            }
            if (wildCardIndex == (searchText.Length - 1))
            {
                var text = searchText.TrimEnd('*');
                return textToSearch.StartsWith(text, StringComparison.InvariantCultureIgnoreCase);
            }                   
        }

        return false;
    }
     
于 2021-07-14T11:51:33.213 回答