考虑到我有以下代码:
let Rx = window['rxjs'];
const { of,
queueScheduler,
asapScheduler,
asyncScheduler,
animationFrameScheduler
} = Rx;
const { observeOn, tap } = Rx.operators;
console.clear();
let source$ = of(1, 2, 3, asapScheduler).pipe(
tap((v) => {
console.log('tap ', v);
}),
)
source$.subscribe((v) => {
console.log('Value ', v);
Promise.resolve().then(() => {
console.log('Microtask value ', v);
});
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/rxjs/6.2.1/rxjs.umd.js"></script>
我使用 asapScheduler 运算符。
根据文档,
asap 将等待当前同步执行的代码结束,然后它会尝试尽快执行给定的任务。
上述代码的执行顺序是什么?它们是如何工作的?我没想到最后会打印tap3
下面是输出,
tap 1
Value 1
tap 2 // here why did this not print Microtask value 1 and Microtask value 2 after printing tap1 and value1?
Value 2
Microtask value 1
Microtask value 2
tap 3
Value 3
Microtask value 3