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我正在尝试使用它的 API 添加对 Google Reader 的订阅，但是我收到以下错误：

执行期满

我在阅读（使用'get'）订阅或标签列表时没有问题。但是当我尝试添加一个子时它超时（使用'post'）

代码是用 Ruby on Rails 编写的，我使用 HTTParty 来处理与 Web 服务的通信。

我的代码如下（我对 Ruby/Rails 还是新手，很抱歉下面包含的任何不良做法。我很高兴有人向我指出）：

class ReaderUser

    # Include HTTParty - this handles all the GET and POST requests.
    include HTTParty

    ...

    def add_feed(feed_url)

      # Prepare the query
      url = "http://www.google.com/reader/api/0/subscription/quickadd?client=scroll"
      query = { :quickadd => feed_url, :ac => 'subscribe', :T => @token }
      query_as_string = "quickadd=#{CGI::escape(feed_url)}&ac=subscribe&T=#{CGI::escape(@token.to_s)}"
      headers = { "Content-type" => "application/x-www-form-urlencoded; charset=UTF-8", "Content-Length" => query_as_string.length.to_s, "Authorization" => "GoogleLogin auth=#{@auth}" }

      # Execute the query
      self.class.post(url, :query => query, :headers => headers)

    end

    ...

end

作为参考，这是我获取令牌的方式：

# Obtains a token from reader
# This is required to 'post' items
def get_token

    # Populate @auth
    get_auth

    # Prepare the query
    url = 'http://www.google.com/reader/api/0/token'
    headers = {"Content-type" => "application/x-www-form-urlencoded", "Authorization" => "GoogleLogin auth=#{@auth}" }

    # Execute the query
    @token = self.class.get(url, :headers => headers)

end

# Obtains the auth value.
# This is required to obtain the token and for other queries.
def get_auth

    # Prepare the query
    url = 'https://www.google.com/accounts/ClientLogin'
    query = { :service => 'reader', :Email => @username, :Passwd => @password }

    # Execute the query
    data = self.class.get(url, :query => query)

    # Find the string positions of AUTH
    auth_index = data.index("Auth=") + 5

    # Now extract the values of the auth
    @auth = data[auth_index,data.length]

end

我很乐意提供所需的任何其他信息。

提前致谢！

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1 回答 1

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经过大量的混乱，我找到了解决方案！

我只需将 Content-Length 设置为“0”。以前我根据我所基于的 PHP 类（greader.class.php）将它设置为“查询”的长度。我提到这一点是为了以防其他人有同样的问题。

于 2011-05-10T14:50:28.300 回答