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不确定标题是否有意义，但这是我的问题以及我是如何到达现在的位置的。

背景：我在一对多设置中有 2 个表。many 表可以有任意数量的记录，这些记录与一个表相关联，但有一个附加列，可以将许多记录标识为 1-7 之间的任何值。我用 7 个 CTE“收集”了每组 1-7 的所有行，然后将它们连接到一个表中，让我了解我的样本数据。

如果单个列中的所有行都为空，那么我想显示一个 *，否则按 GROUPID/GROUPNAME 显示每列中的所有不同值。我有点破解并削减了获得我想要的东西的方式，但有一个警告。如果可能的话，我想在 GROUPID/GROUPNAME 中分别对每一列进行排序，这样 NULL 就不会出现在数据的中间。

这是我的代码，让我陷入了困境：

WITH SAMPLEDATA (CYCLEID,GROUPID,GROUPNAME,COL1,COL2,COL3,COL4,COL5,COL6,COL7)
AS (
SELECT 1,7669,'000000261','GAS',NULL,NULL,NULL,'1',NULL,'00' FROM DUAL
UNION ALL
SELECT 2,7669,'000000261','GAS',NULL,NULL,NULL,'1',NULL,'000000261' FROM DUAL
UNION ALL
SELECT 3,7669,'000000261','GAS',NULL,NULL,NULL,'Chester',NULL,'00' FROM DUAL
UNION ALL
SELECT 4,7669,'000000261','GAS',NULL,NULL,NULL,'Chester',NULL,'000000261' FROM DUAL
UNION ALL
SELECT 5,7669,'000000261','GFG',NULL,NULL,NULL,'1',NULL,'00' FROM DUAL
UNION ALL
SELECT 6,7669,'000000261','GFG',NULL,NULL,NULL,'1',NULL,'000000261' FROM DUAL
UNION ALL
SELECT 7,7669,'000000261','GFG',NULL,NULL,NULL,'Chester',NULL,'00' FROM DUAL
UNION ALL
SELECT 8,7669,'000000261','GFG',NULL,NULL,NULL,'Chester',NULL,'000000261' FROM DUAL
UNION ALL
SELECT 9,7669,'000000261','GKE',NULL,NULL,NULL,'1',NULL,'00' FROM DUAL
UNION ALL
SELECT 10,7669,'000000261','GKE',NULL,NULL,NULL,'1',NULL,'000000261' FROM DUAL
UNION ALL
SELECT 11,7669,'000000261','GKE',NULL,NULL,NULL,'Chester',NULL,'00' FROM DUAL
UNION ALL
SELECT 12,7669,'000000261','GKE',NULL,NULL,NULL,'Chester',NULL,'000000261' FROM DUAL
 ) 
 , GROUPSPROCESSED AS (
SELECT
  GROUPID,
  GROUPNAME,
  CASE
    WHEN cycleid = 1
    THEN NVL(COL1,'*')
    WHEN COL1 = FIRST_VALUE(COL1) OVER (PARTITION BY GROUPNAME ORDER BY GROUPNAME, COL1)
    THEN NULL
    WHEN COL1 = LAG(COL1) OVER (PARTITION BY GROUPNAME ORDER BY GROUPNAME, COL1)
    THEN NULL
    ELSE COL1
  END AS "COL1",
  CASE
    WHEN cycleid = 1
    THEN NVL(COL2,'*')
    WHEN COL2 = FIRST_VALUE(COL2) OVER (PARTITION BY GROUPNAME ORDER BY GROUPNAME, COL2)
    THEN NULL
    WHEN COL2 = LAG(COL2) OVER (PARTITION BY GROUPNAME ORDER BY GROUPNAME, COL2)
    THEN NULL
    ELSE COL2
  END AS "COL2",
  CASE
    WHEN cycleid = 1
    THEN NVL(COL3,'*')
    WHEN COL3 = FIRST_VALUE(COL3) OVER (PARTITION BY GROUPNAME ORDER BY GROUPNAME, COL3)
    THEN NULL
    WHEN COL3 = LAG(COL3) OVER (PARTITION BY GROUPNAME ORDER BY GROUPNAME, COL3)
    THEN NULL
    ELSE COL3
  END AS "COL3",
  CASE
    WHEN cycleid = 1
    THEN NVL(COL4,'*')
    WHEN COL4 = FIRST_VALUE(COL4) OVER (PARTITION BY GROUPNAME ORDER BY GROUPNAME, COL4)
    THEN NULL
    WHEN COL4 = LAG(COL4) OVER (PARTITION BY GROUPNAME ORDER BY GROUPNAME, COL4)
    THEN NULL
    ELSE COL4
  END AS "COL4",
  CASE
    WHEN cycleid = 1
    THEN NVL(COL5,'*')
    WHEN COL5 = FIRST_VALUE(COL5) OVER (PARTITION BY GROUPNAME ORDER BY GROUPNAME, COL5)
    THEN NULL
    WHEN COL5 = LAG(COL5) OVER (PARTITION BY GROUPNAME ORDER BY GROUPNAME, COL5)
    THEN NULL
    ELSE COL5
  END AS "COL5",
  CASE
    WHEN cycleid = 1
    THEN NVL(COL6,'*')
    WHEN COL6 = FIRST_VALUE(COL6) OVER (PARTITION BY GROUPNAME ORDER BY GROUPNAME, COL6)
    THEN NULL
    WHEN COL6 = LAG(COL6) OVER (PARTITION BY GROUPNAME ORDER BY GROUPNAME, COL6)
    THEN NULL
    ELSE COL6
  END AS "COL6",
  CASE
    WHEN cycleid = 1
    THEN NVL(COL7,'*')
    WHEN COL7 = FIRST_VALUE(COL7) OVER (PARTITION BY GROUPNAME ORDER BY GROUPNAME, COL7)
    THEN NULL
    WHEN COL7 = LAG(COL7) OVER (PARTITION BY GROUPNAME ORDER BY GROUPNAME, COL7)
    THEN NULL
    ELSE COL7
  END AS "COL7"
FROM SAMPLEDATA)
SELECT * FROM GROUPSPROCESSED
WHERE COALESCE (COL1,COL2,COL3,COL4,COL5,COL6,COL7) IS NOT NULL
ORDER BY 1,2,3,4,5,6,7,8,9

电流输出： 电流输出

期望的输出： 期望的输出

编辑 这是在任何操作之前从我的示例中导入确切原始数据的代码。从技术上讲，我需要将 3 个表绑定在一起以得出上面的输出。

GROUPPROFILE 包含我上面输出中字段 1-2 的 ID 和 NAME。

COLLVALUES 保存基于 COLLEVELID 为 1-7 的输出中其余字段的数据 (NAME)

GROUPCOLMM 表只是用来连接 GROUPPROFILE.GROUPPROFILEID > COLVALUES.COLVALUEID

CREATE TABLE GROUPPROFILE (GROUPPROFILEID NUMBER(12), SHORTNM NVARCHAR2(30))
REM INSERTING into GROUPPROFILE
Insert into GROUPPROFILE (GROUPPROFILEID,SHORTNM) values (7669,'000000261');

CREATE TABLE COLVALUES (COLVALUEID NUMBER(12), NAME NVARCHAR2(50), COLLEVELID NUMBER(12))
REM INSERTING into COLVALUES
Insert into COLVALUES (COLVALUEID,NAME,COLLEVELID) values (18901,'GFG',1);
Insert into COLVALUES (COLVALUEID,NAME,COLLEVELID) values (106,'GKE',1);
Insert into COLVALUES (COLVALUEID,NAME,COLLEVELID) values (1351,'GAS',1);
Insert into COLVALUES (COLVALUEID,NAME,COLLEVELID) values (423,'0',4);
Insert into COLVALUES (COLVALUEID,NAME,COLLEVELID) values (1,'1',5);
Insert into COLVALUES (COLVALUEID,NAME,COLLEVELID) values (18514,'Chester',5);

CREATE TABLE GROUPCOLMM (GROUPPROFILEID NUMBER(12), COLVALUEID NUMBER(12))
REM INSERTING into GROUPCOLMM
Insert into GROUPCOLMM (GROUPPROFILEID,COLVALUEID) values (7669,1);
Insert into GROUPCOLMM (GROUPPROFILEID,COLVALUEID) values (7669,3);
Insert into GROUPCOLMM (GROUPPROFILEID,COLVALUEID) values (7669,106);
Insert into GROUPCOLMM (GROUPPROFILEID,COLVALUEID) values (7669,1351);
Insert into GROUPCOLMM (GROUPPROFILEID,COLVALUEID) values (7669,16503);
Insert into GROUPCOLMM (GROUPPROFILEID,COLVALUEID) values (7669,18514);
Insert into GROUPCOLMM (GROUPPROFILEID,COLVALUEID) values (7669,18901);
4

1 回答 1

2

您无法从您发布的“原始”数据中获取样本数据。我从子查询 ORIGINALDATA 中的示例数据中对原始数据进行了逆向工程，然后提出了这个解决方案：

WITH SAMPLEDATA (CYCLEID,GROUPID,GROUPNAME,COL1,COL2,COL3,COL4,COL5,COL6,COL7)
AS (
SELECT 1,7669,'000000261','GAS',NULL,NULL,NULL,'1',NULL,'00' FROM DUAL
UNION ALL
SELECT 2,7669,'000000261','GAS',NULL,NULL,NULL,'1',NULL,'000000261' FROM DUAL
UNION ALL
SELECT 3,7669,'000000261','GAS',NULL,NULL,NULL,'Chester',NULL,'00' FROM DUAL
UNION ALL
SELECT 4,7669,'000000261','GAS',NULL,NULL,NULL,'Chester',NULL,'000000261' FROM DUAL
UNION ALL
SELECT 5,7669,'000000261','GFG',NULL,NULL,NULL,'1',NULL,'00' FROM DUAL
UNION ALL
SELECT 6,7669,'000000261','GFG',NULL,NULL,NULL,'1',NULL,'000000261' FROM DUAL
UNION ALL
SELECT 7,7669,'000000261','GFG',NULL,NULL,NULL,'Chester',NULL,'00' FROM DUAL
UNION ALL
SELECT 8,7669,'000000261','GFG',NULL,NULL,NULL,'Chester',NULL,'000000261' FROM DUAL
UNION ALL
SELECT 9,7669,'000000261','GKE',NULL,NULL,NULL,'1',NULL,'00' FROM DUAL
UNION ALL
SELECT 10,7669,'000000261','GKE',NULL,NULL,NULL,'1',NULL,'000000261' FROM DUAL
UNION ALL
SELECT 11,7669,'000000261','GKE',NULL,NULL,NULL,'Chester',NULL,'00' FROM DUAL
UNION ALL
SELECT 12,7669,'000000261','GKE',NULL,NULL,NULL,'Chester',NULL,'000000261' FROM DUAL
 ) 
, originaldata as (
  select distinct groupid, groupname, col, val from sampledata
  unpivot (val for col in (COL1 as 1,COL2 as 2,COL3 as 3,COL4 as 4,COL5 as 5,COL6 as 6,COL7 as 7))
)
select GROUPID, GROUPNAME, 
  case when rn = 1 and col1 is null then '*' else col1 end col1,
  case when rn = 1 and col2 is null then '*' else col2 end col2,
  case when rn = 1 and col3 is null then '*' else col3 end col3,
  case when rn = 1 and col4 is null then '*' else col4 end col4,
  case when rn = 1 and col5 is null then '*' else col5 end col5,
  case when rn = 1 and col6 is null then '*' else col6 end col6,
  case when rn = 1 and col7 is null then '*' else col7 end col7
from (
  select o.*,
  row_number() over(partition by groupid, groupname, col order by val) rn
  from originaldata o
)
pivot(
  max(val) 
  for col in (1 as COL1,2 as COL2,3 as COL3,4 as COL4,5 as COL5,6 as COL6,7 as COL7)
)
order by groupid, groupname, rn;

   GROUPID GROUPNAME COL1      COL2      COL3      COL4      COL5      COL6      COL7     
---------- --------- --------- --------- --------- --------- --------- --------- ---------
      7669 000000261 GAS       *         *         *         1         *         00       
      7669 000000261 GFG                                     Chester             000000261
      7669 000000261 GKE

最好的问候，炖阿什顿

于 2019-08-15T22:26:09.630 回答