1

以下音频以100每分钟节拍数和4/4.

被记录的秒数和滴答声在数量上不断增长。我如何确定：

  • 第一次测量什么时候完成？即第二次1发生..通常计算音乐1, 2, 3, 4, 1, 2, 3, 4
  • 如何确定每个四分音符出现的时间？

(function() {
  var isPlaying = false;

  document.getElementById('togglePlayback').addEventListener('click', function() {
    isPlaying = !isPlaying;
    Tone.Transport.bpm.value = 100;
    Tone.Transport.timeSignature = "4/4";
    console.log('Start playing');
    console.log(Tone.Transport.bpm.value);
    console.log(Tone.Transport.timeSignature);

    if(isPlaying) {
      Tone.Transport.scheduleRepeat(function(time){
        console.log('Seconds: ' + Tone.Transport.getSecondsAtTime(time));
        console.log('Ticks: ' + Tone.Transport.getTicksAtTime(time));
      }, "4n");
      Tone.Transport.start();
    }
  });
})();
<script src="https://cdnjs.cloudflare.com/ajax/libs/tone/13.7.1/Tone.js"></script>
<div>
  <button id="togglePlayback">Start</button>
</div>
<div id="results"></div>

4

1 回答 1

1

由于四分音符是 192 个刻度，您可以使用它来确定其他事件和条件的时间：

(function() {
  Tone.Transport.bpm.value = 100;
  Tone.Transport.timeSignature = "4/4";

  Tone.Transport.scheduleRepeat(function(time){
    console.log('Quarter Notes:', Tone.Transport.getTicksAtTime(time) / 192);
  }, "4n");

  var isPlaying = false;

  document.getElementById('togglePlayback').addEventListener('click', function() {
    if (isPlaying) {
      Tone.Transport.pause();
    } else {
      Tone.Transport.start();
    }

    isPlaying = !isPlaying;
  });
})();
<script src="https://cdnjs.cloudflare.com/ajax/libs/tone/13.7.1/Tone.js"></script>
<div>
  <button id="togglePlayback">Start</button>
</div>
<div id="results"></div>

我还修改了您的逻辑以播放/暂停，而不是安排新的重复，并在每按下一次按钮时从开始播放开始。

于 2019-02-04T17:15:44.870 回答