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我在txt中有这样的数据：

跳蚤,0,0,1,0,0,0,0,0,0,1,0,0,6,0,0,0,6

青蛙,0,0,1,0,0,1,1,1,1,1,0,0,4,0,0,0,5

青蛙,0,0,1,0,0,1,1,1,1,1,1,0,4,0,0,0,5

我需要计算所选列中零的数量，例如在第一列中有 3 个零。

到目前为止，这是我的代码：

        //data patch
        string[] tekst = File.ReadAllLines(@"C:\zoo.txt");


        //full of array 
        string[] tablica = tekst;



        for(int s=0;s<tablica.Length;s++)
        {
            Console.WriteLine(tablica[s]);
        }

        //----------------Show all of array---------------------------//


        //----------------Giv a number of column-----------------////
        Console.WriteLine("Podaj kolumne");

        int a = Convert.ToInt32(Console.ReadLine());

        //Console.WriteLine("Podaj wiersz");

        //int b = Convert.ToInt32(Console.ReadLine());

        int n = tablica.Length;

        int m = tablica[a].Split(',').Length;

       string[,] liczby = new string[n, m];

        for (int j = 0; j < n; j++)
        {
            int suma = 0;
            for (int i = 0; i < m; i++)
            {
               //somethink should be here

            }

        }

解决这个问题的任何想法？

4

1 回答 1

0

尝试：

//data patch
string[] tekst = File.ReadAllLines(@"C:\zoo.txt");


//full of array - you allready have a string[], no need for a new one
//string[] tablica = tekst;



for(int s=0;s<tekst.Length;s++)
{
    Console.WriteLine(tekst[s]);
}

//----------------Show all of array---------------------------//


//----------------Giv a number of column-----------------////
// try to use names with some meaning for variables, for example instead of "a" use "column" for the column 
Console.WriteLine("Podaj kolumne");
int column = Convert.ToInt32(Console.ReadLine());

// your result for zeros in a given column
int suma = 0;

// for each line in your string[]
foreach ( string line in tekst )
{
    // get the line separated by comas
    string[] lineColumns = line.Split(',');
    // check if that column is a zero, remember index is base 0
    if ( lineColumns[column-1] == "0" )
        suma++;
}

Console.WriteLine(suma);

编辑：只需确保验证他们要求的列确实存在于您的数组中，并且如果您不认为第一列是具有名称的列，请调整此部分

lineColumns[column] // instead of lineColumns[column-1]
于 2016-11-07T21:56:53.103 回答