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我想在 IFS 公式中为一个标准使用多个标准。

=IFS(COUNTIFS('DATA'!$A:$A,$A17,'DATA'!$M:$M,"02 - B")=0,"0",(COUNTIFS('DATA'!$A:$A,$A17,'DATA'!$C:$C,"A - Open",'DATA'!$M:$M,"02 - B"))>0,"1",(COUNTIFS('DATA'!$A:$A,$A17,'DATA'!$C:$C,"A - Open",'DATA'!$M:$M,"02 - B")=0)  **(This is where I get stucK) &** ((COUNTIFS('DATA'!$A:$A,$A17,'DATA'!$C:$C,"D - Closed",'DATA'!$M:$M,"02 - B"))<(COUNTIFS('DATA'!$A:$A,$A17,'DATA'!$M:$M,"02 - B"))),"2")

我可能希望使用超过 2 个不同的标准来满足一个 IFS 标准。

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1 回答 1

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你的公式中有几个额外的括号。我无法对此进行测试，因为我没有您的数据或不知道您试图用您的公式实现什么，但是如果您试图结合两个必须为真的条件，那么您将使用 AND 语句并将每个条件与a ，就像我在您编辑的公式中所做的那样：

=IFS(COUNTIFS('DATA'!$A:$A,$A17,'DATA'!$M:$M,"02 - B")=0,"0",
  COUNTIFS('DATA'!$A:$A,$A17,'DATA'!$C:$C,"A - Open",'DATA'!$M:$M,"02 - B")>0,"1",
  AND(COUNTIFS('DATA'!$A:$A,$A17,'DATA'!$C:$C,"A - Open",'DATA'!$M:$M,"02 - B")=0,
  COUNTIFS('DATA'!$A:$A,$A17,'DATA'!$C:$C,"D - Closed",'DATA'!$M:$M,"02 - B")<COUNTIFS('DATA'!$A:$A,$A17,'DATA'!$M:$M,"02 - B")),"2")

由于您显然没有 2016，您可以尝试以下嵌套的 IF 语句：

=IF(COUNTIFS(DATA!$A:$A,$A17,DATA!$M:$M,"02 - B")=0,"0", IF(COUNTIFS(DATA!$A:$A,$A17,DATA!$C:$C,"A - Open",DATA!$M:$M,"02 - B")>0,"1", IF(AND(COUNTIFS(DATA!$A:$A,$A17,DATA!$C:$C,"A - Open",DATA!$M:$M,"02 - B")=0,COUNTIFS(DATA!$A:$A,$A17,DATA!$C:$C,"D - Closed",DATA!$M:$M,"02 - B")<COUNTIFS(DATA!$A:$A,$A17,DATA!$M:$M,"02 - B")),"2","No Conditions Met")))
于 2016-05-18T07:11:27.267 回答