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我有兴趣计算贝叶斯因子来比较 PyMC 3 中的两个模型。根据这个网站，在 PyMC 2 中，该过程似乎相对简单：包括一个伯努利随机变量和一个自定义似然函数，它返回第一个模型的似然性当 Bernoulli 变量的值为 0 时，第二个模型的似然值是 1 时。然而，在 PyMC 3 中，事情变得更加复杂，因为随机节点需要是 Theano 变量。

我的两个似然函数是二项式，所以我想我需要重写这个类：

class Binomial(Discrete):
    R"""
    Binomial log-likelihood.
    The discrete probability distribution of the number of successes
    in a sequence of n independent yes/no experiments, each of which
    yields success with probability p.
    .. math:: f(x \mid n, p) = \binom{n}{x} p^x (1-p)^{n-x}
    ========  ==========================================
    Support   :math:`x \in \{0, 1, \ldots, n\}`
    Mean      :math:`n p`
    Variance  :math:`n p (1 - p)`
    ========  ==========================================
    Parameters
    ----------
    n : int
        Number of Bernoulli trials (n >= 0).
    p : float
        Probability of success in each trial (0 < p < 1).
    """
    def __init__(self, n, p, *args, **kwargs):
        super(Binomial, self).__init__(*args, **kwargs)
        self.n = n
        self.p = p
        self.mode = T.cast(T.round(n * p), self.dtype)

    def random(self, point=None, size=None, repeat=None):
        n, p = draw_values([self.n, self.p], point=point)
        return generate_samples(stats.binom.rvs, n=n, p=p,
                                dist_shape=self.shape,
                                size=size)

    def logp(self, value):
        n = self.n
        p = self.p

        return bound(
            binomln(n, value) + logpow(p, value) + logpow(1 - p, n - value),
            0 <= value, value <= n,
            0 <= p, p <= 1)

关于从哪里开始的任何建议？

4

1 回答 1

3

你可以尝试这样的事情：

with pm.Model() as model:
    p = np.array([0.5, 0.5])
    model_index = pm.Categorical('model_index', p=p)
    model0 # define one model here
    model1 # define the other model here
    m = pm.switch(pm.math.eq(model_index, 0), model0, model1)
    # pass M to a prior or likelihood, for example
    y = pm.SomeDistribution('y', m, observed=data)

    step0 = pm.ElemwiseCategorical(vars=[model_index], values=[0,1])
    step1 = pm.NUTS()
    trace = pm.sample(5000, step=[step0, step1], start=start)

然后您将贝叶斯因子计算为：（必要时添加老化）

pm.traceplot(trace);
pM1 = trace['model_index'].mean()
pM0 = 1 - pM1
pM0, pM1, (pM0/pM1)*(p[1]/p[0])

您可能还想检查如何使用信息标准来比较模型，请参阅此处的示例

于 2016-05-21T15:10:29.417 回答