c++ - 使用函数和头文件从两个单独的输入计算经过的时间

Question

我正在编写一个代码，它需要两个用户输入的时间并将它们全部切换为秒（使用该函数）给我经过的时间并将其存储在我的头文件中，然后写入屏幕经过的时间是 hh:mm:ss。我在使用 Time1 时遇到问题。和 Time.2 以及应该输入冒号的 delim1 和 delim2。我遇到了错误，无法让它运行。我确信还有其他问题。我真的需要帮助我被卡住了！一切都值得赞赏。假设我输入 12:15:30 作为开始时间和结束时间 13:30:30 它应该输出我经过的时间是 1:15:00。任何人都可以弄清楚吗？这听起来很基本，但我迷路了。我什至无法读取数字。这是我的代码：更新应该编译。

#include <iostream>
#include <fstream>
#include "C1A7E1_MyTime.h"

using namespace std;

void DeterminedElapsedTime(const MyTime& Time1,
const MyTime& Time2,
double& ElapsedTimeAsSeconds);

int main()
{
 char *delim1 = ":";


MyTime Time1;
MyTime Time2;

cout << "Input first clocktime and second clocktime (hh:mm:ss  hh:mm:ss)     \n";

cin >> Time1.hours >> delim1 >> Time1.minutes >> delim1 >> Time1.seconds;
cin >> Time2.hours >> delim1 >> Time2.minutes >> delim1 >> Time2.seconds;

// do validation of input, minutes and seconds 0 to 59

double ElapsedTimeAsSeconds = 0.0;

DeterminedElapsedTime(Time1, Time2, ElapsedTimeAsSeconds);
// need to do something with the answer - Convert to HH:MM:SS ?

return 0;
}
//function:
#include"C1A7E1_MyTime.h"
void DeterminedElapsedTime(const MyTime& Time1, const MyTime& Time2, double&      ElapsedTimeAsSeconds)
{

double elapsedtime;

double Time1AsSeconds = Time1.hours * 3600 + Time1.minutes * 60 +   Time1.seconds;
double Time2AsSeconds = Time2.hours * 3600 + Time2.minutes * 60 + Time2.seconds;

ElapsedTimeAsSeconds = Time1AsSeconds - Time2AsSeconds;
}
//header file
struct MyTime {unsigned int hours,  minutes, seconds; };