1

我有 2 个对象数组。第一个是一组经理。第二个是从第一个数组中选择的管理器数组。不同的是我添加了一个属性selected: true。我现在需要用选定的经理替换第一个数组中的经理。我正在使用我创建的 AngularJS 服务来执行此操作。我确信有更简单的解决方案，所以我愿意接受建议。JavaScript、jQuery、lodash、LINQ.js 都不错。我有一个 plunker，我已经显示了我需要的结果。请注意没有该selected:true属性的经理。 截屏

笨蛋

var app = angular.module("mainModule", []);
var MainController = function($scope, service) {

var eventUsers = [
  {
    "event_Users_ID":1009,"event_ID":11,"user_ID":"15e640c1-a481-4997-96a7-be2d7b3fcabb"
  },{
    "event_Users_ID":1010,"event_ID":11,"user_ID":"250a19be-e661-4c04-9a50-c84b0e7349b7"
  },{
   "event_Users_ID":1011,"event_ID":11,"user_ID":"4cada7f0-b961-422d-8cfe-4e96c1fc11dd"
  },{
   "event_Users_ID":1013,"event_ID":11,"user_ID":"a3125317-5deb-426d-bbb1-06d3bd4ebaa6"
  }];
 var managers = [
   {
    "id": "15e640c1-a481-4997-96a7-be2d7b3fcabb",
    "fullName": "Kul Srivastva"
   },{
    "id": "250a19be-e661-4c04-9a50-c84b0e7349b7",
    "fullName": "Todd Brothers"
   }, {
    "id": "4cada7f0-b961-422d-8cfe-4e96c1fc11dd",
    "fullName": "Rudy Sanchez"
   }, {
    "id": "79823c6d-de52-4464-aa7e-a15949fb25fb",
    "fullName": "Mike Piehota",
   }, {
    "id": "a3125317-5deb-426d-bbb1-06d3bd4ebaa6",
    "fullName": "Nick Broadhurst"
  }];                

   $scope.result = service.eventUserMatch(eventUsers, managers);
 };

  function service() {
    var vm = this;

    vm.eventUserMatch = function (eventUsers, managers) {
        var arry = [];
        arry = $.map(eventUsers, function (eventUser) {
            var manager = $.grep(managers, function (user) {
                return user.id === eventUser.user_ID;
            })[0];

            eventUser.id = manager.id;
            eventUser.fullName = manager.fullName;
            eventUser.selected = true;
            return eventUser;
        });
        return arry;
    };
 }

app.controller("MainController", MainController);
app.service('service', service);
4

4 回答 4

2

您可以使用Array#map.

// Get all the event user IDs in an array
var eventUserIds = eventUsers.map(e => e.user_ID);

// Iterate over managers
managers = managers.map(e => {
    // If manager is present in the event users, `select` it
    if (eventUserIds.indexOf(e.id) !== -1) {
        e.selected = true;
    }

    return e;
});


var eventUsers = [{
    "event_Users_ID": 1009,
    "event_ID": 11,
    "user_ID": "15e640c1-a481-4997-96a7-be2d7b3fcabb"
}, {
    "event_Users_ID": 1010,
    "event_ID": 11,
    "user_ID": "250a19be-e661-4c04-9a50-c84b0e7349b7"
}, {
    "event_Users_ID": 1011,
    "event_ID": 11,
    "user_ID": "4cada7f0-b961-422d-8cfe-4e96c1fc11dd"
}, {
    "event_Users_ID": 1013,
    "event_ID": 11,
    "user_ID": "a3125317-5deb-426d-bbb1-06d3bd4ebaa6"
}];


var managers = [{
    "id": "15e640c1-a481-4997-96a7-be2d7b3fcabb",
    "fullName": "Kul Srivastva"
}, {
    "id": "250a19be-e661-4c04-9a50-c84b0e7349b7",
    "fullName": "Todd Brothers"
}, {
    "id": "4cada7f0-b961-422d-8cfe-4e96c1fc11dd",
    "fullName": "Rudy Sanchez"
}, {
    "id": "79823c6d-de52-4464-aa7e-a15949fb25fb",
    "fullName": "Mike Piehota",
}, {
    "id": "a3125317-5deb-426d-bbb1-06d3bd4ebaa6",
    "fullName": "Nick Broadhurst"
}];

var eventUserIds = eventUsers.map(e => e.user_ID);
managers = managers.map(e => {
    if (eventUserIds.indexOf(e.id) !== -1) {
        e.selected = true;
    }

    return e;
})

console.log(managers);
document.getElementById('result').innerHTML = JSON.stringify(managers, 0, 4);
<pre id="result"></pre>

于 2016-01-29T14:11:59.727 回答
1

正如你所说，我确实认为可能有更简单的方法来做到这一点。

我建议你看看SugarJs，它是一个 JavaScript 库，它使用非常有用的方法扩展原生对象。在您的情况下，有关Arrays的文档。

对我来说，处理大量原生 JavaScript 对象 (JSON) 很有帮助。

于 2016-01-29T13:55:41.913 回答
1

这行得通吗？循环遍历新的管理器数组，使用旧管理器数组中匹配管理器对象的 lodash 查找索引，如果找到，用新管理器数组中的管理器替换旧管理器数组中的索引？

可能有一种更有效的方法来编写解决方案，但是假设我正确理解了您的问题，我相信这应该可行吗？无法测试，因为我目前在工作。

for(var i=0; i < SelectedManagersArray.length; i++){
    var index = _.findIndex(OldManagersArray, {id: SelectedManagersArray[i].id, fullName: selectedManagersArray[i].fullName);
//I believe lodash returns a -1 if a matching index isn't found.
    if(index !== -1){SelectedManagersArray[index] = OldManagersArray[i]}
    }
于 2016-01-29T13:57:55.910 回答
1

简单的实现：

for(var i = 0; i < eventUsers.length; i++) {    
    for(var j = 0; j < managers.length; j++) {
        if(eventUsers[i].user_ID === managers[j].id) {
            managers[j].selected = true;
        }
    }
}
于 2016-01-29T14:12:32.787 回答