我正在尝试在 pyqtgraph 中绘制史密斯图。我想知道是否有一种方法可以用半径 = 1 的实圆来剪辑代表假想圆的椭圆项目。这是我到目前为止所做的:我使用了 QGraphicsEllipse 的方法 start angle e span angle,但通过这种方式,也可以绘制圆的垂直线和水平线。matplotlib里面有个方法叫set_clip_path(),不知道pyqtgraph里面有没有这样的东西?
import pyqtgraph as pg
plot = pg.plot()
plot.setAspectLocked()
plot.addLine(y=0)
#vector for real circle
rline = [0.2, 0.5, 1.0, 2.0, 5.0]
#vector for imaginary
xline = [0.2, 0.5, 1, 2, 5]
circle1 = pg.QtGui.QGraphicsEllipseItem(1, -1, -2, 2)
circle1.setPen(pg.mkPen(1))
plot.addItem(circle1)
for r in rline:
raggio = 1./(1+r)
circle = pg.QtGui.QGraphicsEllipseItem(1, -raggio, -raggio*2, raggio*2)
circle.setPen(pg.mkPen(0.2))
plot.addItem(circle)
for x in xline:
#printing the imaginary circle
circle = pg.QtGui.QGraphicsEllipseItem(x + 1, 0, -x*2, x*2)
circle.setPen(pg.mkPen(0.2))
circle.setStartAngle(1440)
circle.setSpanAngle(1440)
plot.addItem(circle)
编辑
这是我的最终代码
plot.setAspectLocked()
plot.setXRange(-1,1, padding = 0)
plot.setYRange(-1,1, padding = 0)
#plot.addLine(y=0)
rline = [0.2, 0.5, 1.0, 2.0, 5.0]
xline = [0.2, 0.5, 1, 2, 5]
circle1 = pg.QtGui.QGraphicsEllipseItem(1, -1, -2, 2)
circle1.setPen(pg.mkPen('w', width=0))
circle1.setFlag(circle1.ItemClipsChildrenToShape)
plot.addItem(circle1)
pathItem = pg.QtGui.QGraphicsPathItem()
path = pg.QtGui.QPainterPath()
path.moveTo(1, 0)
for r in rline:
raggio = 1./(1+r)
path.addEllipse(1, -raggio, -raggio*2, raggio*2)
for x in xline:
path.arcTo(x + 1, 0, -x*2, x*2, 90, -180)
path.moveTo(1, 0)
path.arcTo(x + 1, 0, -x*2, -x*2, 270, 180)
pathItem.setPath(path)
pathItem.setPen(pg.mkPen('g', width = 0.2))
pathItem.setParentItem(circle1)
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