我刚刚安装了学说扩展来使用 Sluggable。
我做这个:
作曲家.json
"stof/doctrine-extensions-bundle": "1.2.*@dev"
应用内核.php
new Stof\DoctrineExtensionsBundle\StofDoctrineExtensionsBundle(),
应用程序/配置/config.yml
stof_doctrine_extensions:
orm:
default:
sluggable: true
Djoo\AppliBundle\Entity\Nomenclature.php
namespace Djoo\AppliBundle\Entity;
use Doctrine\ORM\Mapping as ORM;
use Doctrine\DBAL\Types\SmallIntType;
use Gedmo\Mapping\Annotation as Gedmo;
/**
* Nomenclature
*
*
* @ORM\Table(name="app_nomenclature")
* @ORM\Entity
*/
class Nomenclature
{
.....
/**
* @var string
*
* @ORM\Column(name="titre", type="string", length=200, nullable=false)
*/
private $titre;
/**
* @var string
*
* @ORM\Column(name="finess", type="string", length=10, nullable=true)
*/
private $finess;
/**
* @Gedmo\Slug(fields={"titre","finess"},suffix=".html")
* @ORM\Column(length=128, unique=true,nullable=true)
*/
private $slug;
public function getSlug() {
return $this->slug;
}
public function setSlug($slug){
$this->slug = $slug;
return $this;
}
}
在我的控制器中,我这样做是为了在我的数据表中为旧值生成 slug:
$filterBuilder = $this->get('doctrine.orm.entity_manager')>getRepository('DjooAppliBundle:Nomenclature')->createQueryBuilder('e')->orderBy('e.titre', 'asc');
$query = $filterBuilder->getQuery();
$nomenclatures = $query->getResult();
foreach($nomenclatures as $nomenclaturee){
$nomenclature->setSlug(null);
$this->get('doctrine.orm.entity_manager')->persist($nomenclature);
$this->get('doctrine.orm.entity_manager')->flush();
}
我没有错误,但我的旧值是空蛞蝓。我尝试创建一个新元素,并且我有一个很好的 slug。你有想法吗?
谢谢