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如何从两个 json 文档中找到匹配的数据。例如：我有两个 json 文档和技能 json 文档。

在技​​能文档中：

{

     "_id": "b013dcf12d1f7d333467b1447a00013a",
     "_rev": "3-e54ad6a14046f809e6da872294939f12",
     "core_skills": [
          {
              "core_skill_code": "SA1",
              "core_skill_desc": "communicate with others in writing"
          },
          {
              "core_skill_code": "SA2",
              "core_skill_desc": "complete accurate well written work with attention to detail"
          },
          {
              "core_skill_code": "SA3",
              "core_skill_desc": "follow guidelines/procedures/rules and service level agreements"
          },
          {
              "core_skill_code": "SA4",
              "core_skill_desc": "ask for clarification and advice from others"
          }
      ]}

在员工文件中：

{

  "_id": "b013dcf12d1f7d333467b12350007op",
  "_rev": "3-e54ad6a14046f809e6da156794939f12",
  "employee_name" :"Ashwin",
  "employee_role" : "Software engineer",
  "core_skills":["SA1","SA4"]
}
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1 回答 1

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我不知道你想做什么，但以下内容可能会有所帮助。假设第一个数据集是技能列表及其描述，第二个是员工记录，那么分配给具有合适名称的变量可能如下所示：

var skillCodes = {
  "_id": "b013dcf12d1f7d333467b1447a00013a",
  "_rev": "3-e54ad6a14046f809e6da872294939f12",
  "core_skills": [{
      "core_skill_code": "SA1",
      "core_skill_desc": "communicate with others in writing"
    },{
      "core_skill_code": "SA2",
      "core_skill_desc": "complete accurate well written work with attention to detail"
    },{
      "core_skill_code": "SA3",
      "core_skill_desc": "follow guidelines/procedures/rules and service level agreements"
    },{
      "core_skill_code": "SA4",
      "core_skill_desc": "ask for clarification and advice from others"
    }
  ]};

var employee0 = {
  "_id": "b013dcf12d1f7d333467b12350007op",
  "_rev": "3-e54ad6a14046f809e6da156794939f12",
  "employee_name" :"Ashwin",
  "employee_role" : "Software engineer",
  "core_skills":["SA1","SA4"]
};

创建技能索引使查找特定技能变得更加简单，一些代码可以做到这一点：

var skillCodeIndex = {};
skillCodes.core_skills.forEach(function(item){
  skillCodeIndex[item.core_skill_code] = item.core_skill_desc;
});

现在只需要一个函数来获取特定员工的技能，比如：

function getCoreSkills (employee) {
  console.log('Employee ' + employee.employee_name + ' has the following core skills:');
  employee.core_skills.forEach(function(skill) {
    console.log(skill + ': ' + skillCodeIndex[skill]);
  });
}

一个例子：

getCoreSkills(employee0);

Employee Ashwin has the following core skills:
SA1: communicate with others in writing
SA4: ask for clarification and advice from others

考虑到技能代码和员工实例的构造函数，上述内容可能会变得更加面向对象，我将把它留给你。

于 2014-10-17T22:45:33.957 回答