5

我想要这三个端点:

/games
/images
/games/<game_id>/images

这是我的 settings.py 文件的摘录

#...

games = {
    "schema": {
        "title": {
            "type": "string",
            "required": True
        },
        "name": {
            "type": "string",
            "required": True
        },
    }
}

images = {
    "schema": {
        "game_id": {
            "type": "string",
            "required": True,
        },
        "title": {
            "type": "string",
            "required": True,
        },
    },
    "url": "games/<regex('[a-f0-9]{24}'):game_id>/images"
}
#...

如果省略 url 属性,则在 GET / 时会得到两个预期的端点:

/games

/images

但是,如果您包含 url 属性,则无法点击 /images,而只能点击 /games,/games/<game_id>/images如下所示:

{
    "_links": {
        "child": [
            {
                "href": "/games/<regex('[a-f0-9]{24}'):game_id>/images",
                "title": "games/<regex('[a-f0-9]{24}'):game_id>/images"
            },
            {
                "href": "/games",
                "title": "games"
            }
        ]
    }
}

如何保留集合图像并仍然通过子资源查询使其文档可用?

4

1 回答 1

4

您可以设置 3 个不同的端点,而其中两个正在使用相同的数据库资源(图像)。像这样的东西:

images_schema: {
  "game_id": {
    "type": "string",
    "required": True,
  },
  "title": {
    "type": "string",
    "required": True,
  },
}

games = {
  "schema": {
    "title": {
      "type": "string",
      "required": True
    },
    "name": {
      "type": "string",
      "required": True
    },
  }
}

images = {
  "schema": images_schema,
  "url": "images"  # not really needed
}

games_images = {
  "schema": images_schema,
  "url": "games/<regex('[a-f0-9]{24}'):game_id>/images",
  "datasource": {"source": "images"}
}

有关参考,请参阅多个 API 端点,一个数据源

于 2014-10-03T07:38:21.353 回答