5

有什么比下面的示例更简单的吗?我确实有绑定到 DataGrid lstLinks 的可观察集合(代码中的“列表”)

for (int i = 0; i < list.Count ; i++)
{
    object rowItem = lstLinks.Items[i] ; 
    DataGridRow visualItem =  (DataGridRow)lstLinks.ItemContainerGenerator.ContainerFromItem(rowItem);
    if ( visualItem == null ) break;  
    if (list[i].Changed)
        visualItem.IsSelected = false;
    else
         visualItem.IsSelected = false; 

}
4

4 回答 4

9

萨拉姆麦克米特 :)

是的,有一个更简单的解决方案,您只需将您想要的项目从绑定列表添加到您的 DataGrid SelectedItems 集合中,请参见下面的代码:[如果这篇文章解决了您的问题,请不要忘记标记为答案 :) ]

<Window x:Class="ProgGridSelection.MainWindow"
    xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
    xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
    Title="MainWindow" Height="350" Width="525" Loaded="OnWindowLoaded">
<StackPanel>
    <DataGrid Name="empDataGrid" ItemsSource="{Binding}" Height="200"/>
    <TextBox Name="empNameTextBox"/>
    <Button Content="Click" Click="OnSelectionButtonClick" />
</StackPanel>

public partial class MainWindow : Window
{
    public class Employee
    {
        public string Code { get; set; }
        public string Name { get; set; }
    }

    private ObservableCollection<Employee> _empCollection;

    public MainWindow()
    {
        InitializeComponent();
    }

    private void OnWindowLoaded(object sender, RoutedEventArgs e)
    {
        // Generate test data
        _empCollection =
            new ObservableCollection<Employee>
                {
                    new Employee {Code = "E001", Name = "Mohammed A. Fadil"},
                    new Employee {Code = "E013", Name = "Ahmed Yousif"},
                    new Employee {Code = "E431", Name = "Jasmin Kamal"},
                    new Employee {Code = "E431", Name = "Zuhair Zein"},
                    new Employee {Code = "E431", Name = "Layla Abdullah"},
                };

        /* Set the Window.DataContext, alternatively you can set your
         * DataGrid DataContext property to the employees collection.
         * on the other hand, you you have to bind your DataGrid
         * DataContext property to the DataContext (see the XAML code)
         */
        DataContext = _empCollection;
    }

    private void OnSelectionButtonClick(object sender, RoutedEventArgs e)
    {
        /* select the employee that his name matches the
         * name on the TextBox
         */
        var emp = (from i in _empCollection
                   where i.Name == empNameTextBox.Text.Trim()
                   select i).FirstOrDefault();

        /* Now, add it to your DataGrid SelectedItems collection to
         * add the item to the selected rows
         */
        if (emp != null)
            empDataGrid.SelectedItems.Add(emp);
    }
}
于 2011-03-30T08:17:30.783 回答
1

MVVM 需要更温柔的解决方案,
但它是 MVVM,它是完全可测试且易于维护的。

看看这里 使用 MVVM 管理多个选择

于 2012-06-21T14:44:54.780 回答
0

是的,这个解决方案比侵入 DataGrid 控件要好,如果你只想选择一行,你也可以使用以下代码:

myDataGrid.SelectedItem = item;

其中项目是绑定 DataGrid 的项目之一。

于 2011-03-30T13:17:39.030 回答
0

假设lstLinks是 WPF DataGrid,这会将位置的项目添加i到所选项目:

lstLinks.SelectedItems.Add(lstLinks.Items[i]);

要取消选择所有内容:

lstLinks.SelectedItems.Clear();
于 2021-04-14T14:59:17.427 回答